Something great than AND less than is equal to.
I thibk 10 itself is the answer. It is greater yet less.
Answer:
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
Step-by-step explanation:


![\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20%20%3D%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29)
![\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%3D%28%5Cfrac%7Br%7D%7Bn%7D%20%29)
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]
Answer:
The answer is 29 cm.
Step-by-step explanation:
The side we are looking for is the longest side of the right triangle, called a hypotenuse.
To find it, we first have to square 20, which equals 400. Then, square 21, which equals 441. Next, add 400 and 441 to make 841, then find the square root of 841, which is 29.
I hope this helped! :-)
Square root of 4096 is 6.4 so the answer is 64 + 6.4 = 70.4.