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Klio2033 [76]
3 years ago
6

Rebecca has 21 math problems to solve. She has solved 2-7 of them. How many problems has she solved

Mathematics
1 answer:
Blizzard [7]3 years ago
7 0
She has solved 6 problems.  21/7 times 2 equals 6.
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Solve for variable y answer in simplest radical form
ASHA 777 [7]

Answer:

option A

Step-by-step explanation:

option A y = 9√3 is the correct answer .

In∆ PQR

cos 30 = y /18

√3/2 = y / 18

y = 9√ 3

plz mark my answer as brainlist plzzzz.

hope this will be helpful to you .

4 0
3 years ago
Tessa bought stock in a restaurant for $173.00. Her stock is now worth $242.20. What is the percentage increase of the value of
frozen [14]

Answer:

The percentage increase in Tessa's stock is 40%

Step-by-step explanation:

Given that:

Previous worth = $173

Worth now = $242.20

We have to find percentage increase which can be known by subtracting previous worth from present worth and multiplying it by 100:

Percentage increase = $242.20 - $173 = $69.2

Percentage increase = $69.2/173 *100

Percentage increase = 40%

i hope it will help you!

7 0
4 years ago
Find the pattern. What numbers come next?
Ilia_Sergeevich [38]

Answer:

D

Step-by-step explanation:

the pattern is -6 to get the next number

3 0
3 years ago
Read 2 more answers
Maddy made $22.50 for babysitting for 5 hours for her aunt. Maddy was paid $21.00 for 3.5 hours of babysitting for her neighbor.
Greeley [361]

Answer:Her Aunt paid her 4.50 and hour and her neighbor 6 an hour. The difference is 1.5

Step-by-step explanation:

8 0
3 years ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
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