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3 years ago

I need help asap Please

Mathematics

1 answer:

stepladder [879]3 years ago

6 0

I’m not sure let me get back to u on that

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Choose the answers that have a repeating decimal?

Dmitry [639]

A 0.66... that the repeating decimals

4 0

3 years ago

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

3 years ago

When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval

Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

$\alpha = 1-99$ %

$=1-0.99$

$=0.01$

then,

$\frac{\alpha}{2} =\frac{0.01}{2}$

$=0.005$

or,

$Z_{\frac{\alpha}{2} }=Z_{0.005}$

$=2.576$

Now,

The point estimate will be:

⇒ $\hat{P}=\frac{x}{n}$

⇒ $=\frac{110}{343}$

⇒ $=0.321$

or,

⇒ $1-\hat{P}=1-0.321$

⇒ $=0.679$

The margin of error will be:

⇒ $E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )$

On substituting the above values, we get

⇒ $=2.576\times \sqrt{\frac{0.321\times 0.679}{343} }$

⇒ $=2.576\times \sqrt{\frac{0.217959}{343} }$

⇒ $=0.065$

hence,

⇒ $\hat{P}-E$

⇒ $0.321-0.065$

⇒ $0.256,0.386$

6 0

3 years ago

Nick buys 2 shirts and 4 hats for a total of $44.00. Hours f the hats cost $5.00 each,how much does each shirts costs

skad [1K]

Answer:

Each shirt costs 12$

Step-by-step explanation:

Simple steps :)

1. Times 4 by 5 which equals 20

2. Next subtract 20 by 44 which is 24

3. Now take 24 and divide by 2 (Since there are 2 shirts) this is you answer

One shirt costs 12$

Hope this helped have a GOOD day :)

8 0

3 years ago

What role do Statistics play in politics? Explain and give at least 3 important points.

bezimeni [28]

Answer:

1:Statistics are us in methosts

2:refere ti indevidgual data

7 0

3 years ago