since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
It is known that 6 things can get arranged in 720 ways, let's look at the math of this.
There are six things so:
1×2
2×3
6×4
24×5
120×6
720
I found the choices that should have been included in this problem.
a) (1.5,26)
b) (2.25,30)
c) (5.5,88)
d) (7.25,110)
y = 16x
choice a. y = 16(1.5) = 24
choice b. y = 16(2.25) = 36
choice c. y = 16(5.5) = 88
choice d. y = 16(7.25) = 116
The correct answer is choice c. (5.5, 88)
Answer:
A=45m^2
Step-by-step explanation:
l*w
