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HACTEHA [7]
4 years ago
5

Describe a pattern and predict the next number in the pattern

Mathematics
1 answer:
MrMuchimi4 years ago
3 0
You'd have to provide the pattern...
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Log 15 = log(7 - 4x)​
Korvikt [17]

Answer:

x =-2

Step-by-step explanation:

log 15 = log(7 - 4x)​

The terms inside the log functions must be the same

15 = 7 -4x

Subtract 7 from each side

15-7 = 7-4x-7

8 = -4x

Divide  each side by -4

8/-4 =-4x/-4

-2 =x

7 0
3 years ago
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Could someone please see if I'm correct, and explain :D
arlik [135]
Yeah I'm pretty sure that's the simplest form
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3 years ago
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Simplify please (3^2 x^4)^5
lubasha [3.4K]

Answer:

59049x^20

Step-by-step explanation:

3^2=9

9^5= 59049

x^4*5= x^20

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3 years ago
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Help pls! no explanation needed just the answers :)
Phoenix [80]

Answer: A

13+4=17

Step-by-step explanation:

I want Brainlist

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3 years ago
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A lot of 25 skylight covers are received at your construction site, and before installation are subjected to an acceptance testi
8090 [49]

Answer:

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

Step-by-step explanation:

We have a population of N=25 skylight covers, were K=4 are defective.

We sample n=5 covers, and we will accept the lot if k=2 or fewer are defective.

We will use the hypergeometric distribution to model this probabilities.

First, to be accepted, the sample can have 2, 1 or 0 defective covers, so the probability of being accepted is:

P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)

The probability that there are k defective covers in the sample is:

P(k)=\dfrac{\dbinom{k}{k}\dbinom{N-k}{n-k}}{\dbinom{N}{n}}

Then, we can calculate the individual probabilities as:

P(k=0)=\dfrac{\dbinom{4}{0}\cdot \dbinom{25-4}{5-0}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{0}\cdot \dbinom{21}{5}}{\dbinom{25}{5}}\\\\\\P(k=0)=\dfrac{1\cdot 20349}{53130}=0.38

P(k=1)=\dfrac{\dbinom{4}{1}\cdot \dbinom{25-4}{5-1}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{1}\cdot \dbinom{21}{4}}{\dbinom{25}{5}}\\\\\\P(k=1)=\dfrac{4\cdot 5985}{53130}=0.45

P(k=2)=\dfrac{\dbinom{4}{2}\cdot \dbinom{25-4}{5-2}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{2}\cdot \dbinom{21}{3}}{\dbinom{25}{5}}\\\\\\P(k=2)=\dfrac{6\cdot 1330}{53130}=0.15

If we add this probabilities, we have:

P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)\\\\P(accepted)=0.38+0.45+0.15=0.98

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

6 0
3 years ago
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