9514 1404 393
Answer:
| 573 |
Step-by-step explanation:
The product of a 1×2 matrix and a 2×1 matrix will be a 1×1 matrix. The value of the only term will be the dot-product of the row of the first matrix and the column of the second matrix.
P = | 17·27 +19·6 | = | 573 |
101.65 x .30= 30.50 saving
so take 101.65 - 30.50= 71.15
Answer:
<u>the prime factors of 630 are 2, 3, 5, 7. Therefore, the product of prime factors = 2 × 3 × 5 × 7 = </u><u>2</u><u>1</u><u>0</u>
Answer:
اhello : tan θ = - 12/5
Step-by-step explanation:
tan θ = sin θ / cos θ .... (*)
(cosθ)² + (sinθ)² = 1 ... (**)
theta is in quadrant 2 : cosθ ≤ 0
Substitute sinθ = 12/13 into (**) and solve for cosθ :
(cosθ)² + (12/13)² = 1
(cosθ)² = 1 - 144/169
(cosθ)² = 25/169
cosθ = - 5 /13 because cosθ ≤ 0
by (*) : tan θ = (12/13)/ (-5/13) = (12/13) ×(-13/5)
tan θ = - 12/5
Answer:
(0, -3)
Step-by-step explanation:
Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."
Rearranging x^2+y^2+6y-72=0, we get x^2 + y^2 + 6y = 72.
x^2 is already a perfect square. Focus on rewriting y^2 + 6y as the square of a binomial: y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:
x^2 + y^2 + 6y + 9 - 9 = 72:
x^2 + (y + 3)^2 = 81
Comparing this to the standard equation of a circle with center at (h, k) and radius r,
(x - h)^2 + (y - k)^2 = r^2. Then h = 0, k = -3 and r = 9.
The center of the circle is (h, k), or (0, -3).
