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ipn [44]
3 years ago
10

PLEASE HELP ASAP WILL MARK BRAINLIEST Solve the quadratic equation 18x^2 -153x -172 =0

Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0
X=9.51 or x=-1.01 (to 3 sf)
if you want exact value just continue from where i left off from the pic :)
its the quadratic formula i think thats the name of it

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(6x10^2)/(3x10-5) help what is this in standard form?
Tasya [4]

<u>Answer: </u>

The standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

<u>Solution: </u>

Given that \frac{6 \times 10^{2}}{3 \times 10^{-5}} ---- eqn 1

To write\frac{6 \times 10^{2}}{3 \times 10^{-5}} in standard form,

We know that \bold{\frac{1}{a^{-m}} = a^{m}} .So \frac{1}{10^{-5}}  becomes 10^{5}.

Now eqn 1 becomes,

= \frac{6 \times 10^{2}}{3} \times 10^{5} ----- eqn 2

We know that \bold{a^{m} \times a^{n}=a^{m+n}}, so 10^{2} \times 10^{5} = 10^{7}

Now eqn 2 becomes,

= \frac{6}{3} \times 10^{7}

= 2 \times 10^{7} ---- eqn 3

Expanding 10^{7}:  

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

Now eqn 3 becomes,

= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

= 20,00,0000  

Hence the standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

6 0
3 years ago
Round each number to the nearest thousand and add 29,847+31,866+49,230
lbvjy [14]

111,000 because you do 30000+32000+49000.

3 0
2 years ago
WAZZUP<br> :)<br> have a nice day
mamaluj [8]
hello! have a nice day :D
3 0
2 years ago
Read 2 more answers
Factorise 2c power of 2-12c+6cd​
irakobra [83]

Answer:

2c*(-4 + 3d)

Step-by-step explanation:

To factorize the equation 2c*2 -12c+6cd, put the common term 2c out and you would get:

2c*2 -12c+6cd

= 4c - 12c + 6cd

= -8c + 6cd

= 2c*(-4 + 3d)

This is the simpliest form you can get

Hope it helped :3

5 0
2 years ago
Help please and thanks
Ivan

Answer:

a function

Step-by-step explanation:

trust the process

6 0
2 years ago
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