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Reptile [31]
4 years ago
10

The encapsulation unit on the data link layer of the osi model is _________

Computers and Technology
1 answer:
bazaltina [42]4 years ago
7 0
<span>The encapsulation unit on the data link layer of the OSI model is the Date link, layer 2.</span>
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The output is second half of the month, refers to both

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3 years ago
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List and explain three ways study groups benefit your learning.
SashulF [63]

Answer:

Studying in groups can have many effective outcomes and be beneficial. Here are some ways studying in a group is benefical,

1.  More support, limits chances of procrastination

<u>      With many people, everyone is assigned a role or there is more determination by all peoples to get the work done than an individual being the only one responsible than many trying to accomplish the completion of the project. </u>

2. More people means more parts can get done effectively and taking notes is easier.

<u>      More people allow the work (depending on the project of assignment) for the work to get more focused and worked on faster with the designated roles given. </u>

3. More interactive and allows (sometimes an enjoyable times) and to even learn faster than independently.

      People, not all however, might like the company, there's support and even people skills is enhanced by being in the group.

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3 years ago
4. In this problem, we consider sending real-time voice from Host A to Host B over a packet-switchednetwork (VoIP). Host A conve
mina [271]

Answer:

The time elapsed is 0.017224 s

Solution:

As per the question:

Analog signal to digital bit stream conversion by Host A =64 kbps

Byte packets obtained by Host A = 56 bytes

Rate of transmission = 2 Mbps

Propagation delay = 10 ms = 0.01 s

Now,

Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.

Time taken to generate and convert all the bits into digital signal is given by;

t = \frac{Total\ No.\ of\ packets}{A/D\ bit\ stream\ conversion}

t = \frac{56\times 8}{64\times 10^{3}}          (Since, 1 byte = 8 bits)

t = 7 ms = 0.007 s

Time Required for transmission of the packet, t':

t' = \frac{Total\ No.\ of\ packets}{Transmission\ rate}

t' = \frac{56\times 8}{2\times 10^{6}} = 2.24\times 10^{- 4} s

Now, the time elapse between the bit creation and its decoding is given by:

t + t'  + propagation delay= 0.007 + 2.24\times 10^{- 4} s + 0.01= 0.017224 s

8 0
3 years ago
Write the definition of a method printDottedLine, which has no parameters and doesn't return anything. The method prints to stan
Bond [772]

Answer:

public static void printDottedLine()

{

  System.out.println(".....");

}

Explanation:

The above written code is in JAVA and it is the method definition of the method mentioned in the question.Since the method returns nothing hence it's return type is void and it does not have any arguments hence there is nothing written in the parenthesis.In JAVA System.out.println is used for standard output and trminates them by newline.

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3 years ago
Which logic gate produces an output of 1 only if both its inputs are 0
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0=false

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+ operator = and function

AND GATE

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