Answer:
20
Step-by-step explanation:
If you work this out you get 1:
5/100*20
5 divided by 100 is 0.05 then 0.05 times 20 is 1
You would put 151 dollars in your account at October.
16+15+15+15+15+15+15+15+15+15=151
Answer:
a - b = 12
Step-by-step explanation:
Given
= 12 ← factor the numerator
a² - b² ← is a difference of squares and factors as
a² - b² = (a - b)(a + b)
Thus
= 12
Cancel the common factor (a + b) on numerator/ denominator, thus
a - b = 12
You have the correct answer. Nice work. If you need to see the steps, then see below
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First we need to find the midpoint of H and I
The x coordinates of the two points are -4 and 2. They add to -4+2 = -2 and then cut that in half to get -1
Do the same for the y coordinates: 2+4 = 6 which cuts in half to get 3
So the midpoint of H and I is (-1,3). The perpendicular bisector will go through this midpoint
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Now we must find the slope of segment HI
H = (-4,2) = (x1,y1)
I = (2,4) = (x2,y2)
m = (y2 - y1)/(x2 - x1)
m = (4 - 2)/(2 - (-4))
m = (4 - 2)/(2 + 4)
m = 2/6
m = 1/3
Flip the fraction to get 1/3 ---> 3/1 = 3
Then flip the sign: +3 ----> -3
So the slope of the perpendicular bisector is -3
-----------------------
Use m = -3 which is the slope we found
and (x,y) = (-1,3), which is the midpoint found earlier
to get the following
y = mx+b
3 = -3*(-1)+b
3 = 3+b
3-3 = 3+b-3
0 = b
b = 0
So if m = -3 and b = 0, then y = mx+b turns into y = -3x+0 and it simplifies to y = -3x
So that confirms you have the right answer. I've also used GeoGebra to help confirm the answer (see attached)
Answer:
970m^{2}
Step-by-step explanation:
This polygon can be divided in two figures: one is a triangle, an the other one is a square.
We'll begin calculating the triangle's area, using the following formula:

Where:


As you can see, I added both sides of the triangle that measure 9 m and also the lenght of the square that measures 20 m! This added up is what the base of the triangle measures on total.



Now we are going to calculate the square's area, that is much more simple:

Where:


To know the whole figure's area, we add up both areas:
