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DochEvi [55]
3 years ago
11

An initial deposit of $45,000 grows at an annual rate of 10% for 20 years. Compare the final balances resulting from continuous

compounding and annual compounding. (Round your answers to the nearest cent.)
Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer:

Annual:         $302 737.50

Continuous: $332 507.52

Step-by-step explanation:

A. Compounded annually

The formula for <em>compound interest</em> is

A = P(1 + r)ⁿ

Data:

P = $45 000

r  = 10 %

t = 20 yr

Calculations:

n = 20

A = 45 000(1+ 0.10)²⁰

  = 45 000 × 1.10²⁰

  = 45 000 × 6.727 499 95

  = $302 737.50

B. Compounded continuously

The formula for <em>continuously compounded inerest</em> is

A = Pe^{rt}

A = 45 000e^{0.10 \times20}

= 45 000e^{2.0}

  = 45 000 × 7.389 056 61

  = $332 507.52

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The merchandise is marked up 11%. This means you pay 100% of the price plus 11%. We can represent that as (1+r) where r is the percent marked above. For 11%, this expression would be 1+0.11. We multiply that by the price p. p(1+0.11). This simplifies to p+0.11p. We can further simplify it to 1.11p.

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Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter
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Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events <em>A</em> and <em>B</em> are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

P(A\cap B)=0

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, P(A\cap B)=0.

Events A and B are independent  if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, P(A\cap B)=P(A)\times P(B).

The concepts of mutually exclusive events and independent events are not the same.

(e)

As the it is provided that A and B are mutually exclusive events, we know that P(A\cap B)=0.

Now compute the value of P(A)\times P(B) as follows:

               P(A)\times P(B)=0.30\times 0.40=0.12\neq 0

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

4 0
3 years ago
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