Solve for x: round to nearest tenth

Ostrovityanka [42]

Umm i would not trust that file

5 0

3 years ago

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

Anvisha [2.4K]

Answer:

Probability will be 0.5779

Step-by-step explanation:

Number of tablets n = 19

Probability of defect rems that is p = 0.03

Here number of trials is fixed and probability of success = 0.03

Here p = 0.03

So q = 1 - p = 1 -0.03 = 0.97

By using binomial distribution

Probability is given by $^nC_rp^rq^{n-r}$

So P(0 or 1) = $^{19}C_0{0.03}^0{0.97}^{19-0}+^{19}C_1{0.03}^1{0.97}^{19-1}=0.5606+0.0173=0.5779$

4 0

3 years ago

Two equations are given below: a – 3b = 22 a = b – 2 What is the solution to the set of equations in the form (a, b)? (–10, –8)

aliya0001 [1]

Hi Kristian

a - 3b = 22
a = b - 2

We need to solve a = b -2 for a
First, we need to substitute b - 2 for a in a - 3b = 22
a - 3b = 22
b - 2 - 3b = 22
-2b - 2 = 22
-2b = 22 + 2
-2b = 24
b = 24/-2
b = -12

Now substitute -12 for b in a = b - 2
a = b -2
a= -12 - 2
a= -14

Thus, the solution is a = -14 and b = -12

The correct option is the last one (-14,-12)

If you have questions about my answer, please let me know.

Good luck!

4 0

3 years ago

5у - 4х = -7 <br>2y + 4x = - 14

Nuetrik [128]

1. Y= 5/4x -1.4
2.Y=-2/4x -7
Formula is Y=MX+B
To solve these equations you have to make the Y separate so add or subtract the x value depending on the charge remember what you do to one side you do to the other after you divide everything by the number in the Y value and for the x you put the y value on-top and make it a fraction

3 0

3 years ago

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: