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dexar [7]
4 years ago
15

Please help with numbers 2-5. thank you

Mathematics
1 answer:
Alex73 [517]4 years ago
8 0
2. D
3. 2t^3 -4t^2 -3t-4
4. D
5. C
And the work I did to get the answers is in the picture

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Answer:

Step-by-step explanation:

its A

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A ladder is resting against a wall. The ladder and the ground make an angle of 45° and the ladder is 7 ft from the wall. How lon
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The ladder is 10 ft long (9.899 ft to be more precise).
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The point A, with coordinates (0,a,b) lies on the line l1, which has equation:
Luda [366]

a) The solution of the system is: (λ, a, b) = (- 5, - 11, - 26).

b) The coordinates of the point P are (x, y, z) = (- 16 / 3, - 43, 152 / 3).

c) Vectors <u>AP</u> and <u>PB</u> are <em>collinear</em> for their ends lie on the line. The ratio AP : PB is 83.248 : 73.491 (1.133 : 1).

<h3>How to analyze a line equation in vector form</h3>

a) In this problem we have a equation of the line in <em>vector</em> form, whose form is:

<u>r</u> = (5, 19, - 1) + λ · (1, 6, - 5)

Now we find the value of λ for the case <u>r</u> = (0, a, b):

(0, a, b) = (5, 19, - 1) + λ · (1, 6, - 5)

5 + λ = 0

19 + 6 · λ = a

- 1 + 5 · λ = b

The solution of the system is: (λ, a, b) = (- 5, - 11, - 26).

b) Then, the following condition must be fulfilled:

<u>OP</u> • <u>PB</u> = 0

(5 + λ, 19 + 6 · λ, - 1 + 5 · λ) • [(4, 13, 4) - (5 + λ, 19 + 6 · λ, - 1 - 5 · λ)] = 0

(5 + λ, 19 + 6 · λ, - 1 + 5 · λ) • (- 1 - λ, - 6 - 6 · λ, 5 + 5 · λ) = 0

(5 + λ) · (- 1 - λ) + (19 + 6 · λ) · (- 6 - 6 · λ) + (- 1 + 5 · λ) · (5 + 5 · λ) = 0

- (5 + λ) · (1 + λ) - 6 · (19 + 6 · λ) · (1 + λ) + 5 · (- 1 + 5 · λ) · (1 + λ) = 0

- (5 + 6 · λ + λ²) - 6 · (19 + 25 · λ + 6 · λ²) + 5 · (- 1 + 4 · λ + 5 · λ²) = 0

- 5 - 6 · λ - λ² - 114 - 150 · λ - 36 · λ² - 5 + 20 · λ + 25 · λ² = 0

- 12 · λ² - 136 · λ - 124 = 0

There are two solutions: λ₁ = - 1, λ₂ = - 31 / 3, whose points P are:

<u>r₁</u> = (5, 19, - 1) + (- 1) · (1, 6, - 5)

<u>r₁</u> = (4, 13, 4)

<u>r₂</u> = (5, 19, - 1) + (- 31 / 3) · (1, 6, - 5)

<u>r₂</u> = (- 16 / 3, - 43, 152 / 3)

Then, the coordinates of the point P are (x, y, z) = (- 16 / 3, - 43, 152 / 3).

c) Vectors <u>AP</u> and <u>PB</u> are <em>collinear</em> for their ends lie on the line. The ratio can be found by using the magnitudes of each vector:

Vector AP

<u>AP</u> = (- 16 / 3, - 43, 152 / 3) - (0, - 11, - 26)

<u>AP</u> = (- 16 / 3, - 32, 230 / 3)

AP = √(<u>AP</u> • <u>AP</u>)

AP ≈ 83.248

Vector PB

<u>PB</u> = (4, 13, 4) - (- 16 / 3, - 43, 152 / 3)

<u>PB</u> = (28 / 3, 56, - 140 / 3)

PB = √(<u>PB</u> • <u>PB</u>)

PB ≈ 73.491

The ratio AP : PB is 83.248 : 73.491 (1.133 : 1).

To learn more on lines: brainly.com/question/17188072

#SPJ1

8 0
2 years ago
Find the measures of angle AOC and angle COB in the graph​
OleMash [197]

The line perfectly cuts the 90 degree angle in half, as shown by the proportional x and y movement. Meaning that the angles are both 45 degrees

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4 years ago
Which shows the following expression after the negative exponents have been eliminated? m^7 n^3/ mn^-1 assume m=0 and n=0
aliina [53]

Given expression is \frac{m^7n^3}{mn^{-1}}.

where m \neq 0, n \neq 0,

Now we have to simplify this and find the next step so that negative exponent gets eliminated.

We know that when negative exponent changes sign, then it moves from numerator to denominator or from denominator to numerator as shown in the formula:

x^{-m}=\frac{1}{x^m}

or\frac{1}{x^{-m}}=x^{m}


n has negative exponent in denominator so it will move to numerator and we get:

\frac{m^7n^3n^1}{m}

or \frac{m^7n^3n}{m}

Hence final answer is \frac{m^7n^3n}{m}.

8 0
3 years ago
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