Answer: 2n^2+3n-4
1st differnce is 3, 7, 11, 15
2nd differnce is 4
so its 2n^2
we compare it to teh 2n^2 sequence
2 8 18 32 50
-1 2 9 20 35
difference is 3, 6, 9, 12,15
so it is 3n-4
Well 2.7182818284 is from euler's constant e.
Integers are whole numbers positive and negative. since 2.7182818284 is positive (and you can't take square root of negative number) the integers we find will be positive.
List out square roots.
sqrt1 = 1
sqrt 2 = 1.41
sqrt 3 = 1.73
sqrt 4 = 2
sqrt 5 = 2.2
sqrt 6 = 2.4
sqrt 7 = 2.6
sqrt 8 = 2.8 -----> this is over the constant.
so it's between the square root of 7 and 8
Answer:
Step-by-step explanation:
the system is : 3x + y + 2 = 0.......(1)
2x - y + 3 = 0......(2)
x+
py - 3 = 0......(3)
(1)+(2) : 3x+y+2 +2x-y+3 =0
5x+5 =0
so : x = -1
put x = -1 in equation (2) : 2(-1)-y+3 = 0
so : y = 1
the intersection point is A(-1 ; 1)
put x = -1 and y = 1 in equation (3) : -1+p(1)-3 =0 so : p = 4
sketch the line :3x + y + 2 = 0 and 2x - y + 3 = 0 and x+
4y - 3 = 0
y = -3x-2 ...(color red) and y=2x+3....(color blue) and y = -1/4x +3/4...(color purple)