Answer:
<em>x=-6, x=1</em>
Step-by-step explanation:
<u>The zero product property</u>
It states that if a.b=0, then it must be satisfied that a=0 or b=0. It's commonly used to solve equations where one of the sides is 0.
The given equation is:
(x+2)(x+3)=12
Since neither side is 0, we operate the expression:
x^2+3x+2x+6=12
Moving 12 to the left side and simplifying:
x^2+3x+2x+6-12=0
x^2+5x-6=0
Factoring:
(x+6)(x-1)=0
Now, since there is zero on the right side, we apply the property to solve:
x+6=0, or x-1=0
The two solutions come directly:
x=-6, x=1
Answer:
132
Step-by-step explanation:
X = 132
Answer:
The answer is the option D
and 
Step-by-step explanation:
we have
we know that
The solution of the system of equations is the intersection point both graphs
Using a graphing tool
see the attached figure
The solution are the points 
and 
therefore
The solution of the equation 
are
so
For 
For 
therefore
and because the intersection points are common points for both graphs
Answer:
Step-by-step explanation:
Since the coefficient of x^2 is positive, this quadratic is a parabola in the shape of a U, hence has a minimum.
We want to end up with the form (x-h)^2 + c. Since (x-h)^2>=0, this form shows that the minimum is achieved when x=h.
Completing the square will put the quadratic in the desired form. Note that:
(x-h)^2=x^2-2hx+h^2
Comparing this with the given form, we must have -8=-2h, or h=4. But we are missing h^2=4^2=16. We can add the missing 16 and subtract it elsewhere without changing the quadratic.
x^2-8x+16 + (16-4) = (x-4)^2 + 12
Now we know that at x=4 the quadratic has a minimum and that the minimum is 12.
Answer:
Step-by-step explanation:
<u>Given recursive formula</u>
- a₁ = 0
- aₙ = 2(aₙ₋₁)² - 1, for n>1
<u>The first 5 terms are:</u>
- a₁ = 0
- a₂ = 2(0)² - 1 = 0 - 1 = -1
- a₃ = 2(-1)² - 1 = 2 - 1 = 1
- a₄ = 2(1)² - 1 = 2 - 1 = 1
- a₅ = 2(1)² - 1 = 2 - 1 = 1
