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3 years ago

Find the solution of the systems of equations x=8+y and x-11y= -12

1 answer:

7 0

<span>x - y = 8
x -11y = -12
----------------subtract
10y = 20
y = 2

x - 2 = 8
x = 10

answer
(10, 2) is the solution of the system

</span>

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What type of triangle (right, obtuse, acute) do the angles 5,5,5 form?

ziro4ka [17]

Answer:

acute

Step-by-step explanation:

5 is lower than a 90* angle

if this is wrong I'm very sorry.

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3 years ago

The difference between 3 times a number and 21

pashok25 [27]

The difference (-) between 3 times a number (3n) and 21.

3n - 21

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3 years ago

AARP reported on a study conducted to learn how long it takes individuals to prepare their federal income tax return (AARP Bulle

Crank

Answer:

Confidence interval: (30.1,36.9)

Step-by-step explanation:

We are given the following data set:

35.3,30.5,37.4,26.5,13.0,49.9,28.8,44.0,61.6,0.5,40.5,34.9,47.9,36.6,24.1,39.8,47.8,18.5,36.6,39.2,14.5,37.3,40.5,49.3,45.5,28.3,19.5,5.6,52.6,41.4,45.3,39.0,33.7,29.4,14.5,40.1,33.7,36.9,5.6,33.7

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1339.9}{40} = 33.5$

$S.D = 11$ (given)

n = 40

Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$33.5 \pm 1.96(\frac{11}{\sqrt{40}} ) = 6.34 \pm 3.4 = (30.1,36.9)$

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3 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ?

Alja [10]

Using the factor theorem, it is found that the polynomial is:

$f(x) = x^3 - 2x^2 - 3x + 6$

Given by the first option

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Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ using the factor theorem it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.