Answer:The pressure of Mercury = 588,600Pa
Explanation:
The pressure of Mercury is given as
p=h x ρ x g
Where h =height= 20 dm
changing to meters
10 decimeters (dm) =1 meter
20dm =2 meter, 2m
ρ is the density =30000-kg/m³
g , gravity = 9.81-m/s²
Pressure = 2.0m x 30000-kg/m³ x 9.81-m/s²
588,600 kg.m/ s²/m² =588,600 N/m²
The pressure of Mercury=588,600Pa
Answer: The right to privacy includes the ability to guard one's wealth and body from government interference. Residents have conferred the capacity to perform their own legal choices for themselves.
Explanation:
The right to privacy is a component of several legal conclusions to hold governmental and individual activities that endanger the privacy of people. Over 150 political structures consider the right to privacy.
Answer and Explanation:
"Blocked opportunity" is the term that defines the state when a particular person is not able to achieve the desired goal due to the society or any other factor. The opportunity that the person is waiting for or had high hopes with goes away from the hand , this situation leaves the person in the state of sadness or depression.
This state also leads to stain the person and his thoughts. The situation of strain and delinquency sometime lead to criminal tendencies as well according to many theories. Crime causing act is performed towards the society because the person starts to blame society element behind the failure of not achieving the goal and unsuccessful.
Answer:
The Bulk density = 1.3 g/cm³
the porosity of the sample is 132 cm³
Explanation:
Given:
Volume of cylinder = 260 cm³
Mass of container and the soil = 403 g
Mass of the empty container = 65 g
Thus,
The mass of the soil is = 403 - 65 = 338 g
Now,
The Bulk density = 
or
The Bulk density = 
or
The Bulk density = 1.3 g/cm³
also,
average particle density for mineral soil is usually given as 2.65 g/cm³
i.e the air present in the given soil sample has reduced its density from 2.65 g/cm³ to 1.3 g/cm³
The mass of the whole sample = Volume × Density
= 260 × 2.65
= 689 gm
but,
The actual mass of the dry sample = 338 g
thus,
Mass of air in the sample = 689 - 338 = 351 g
Therefore,
the volume of 351 g soil = 
= 
= 132.45 cm³
so the porosity of the sample is 132 cm³
After looking at the photograph given above, one sedimentary rock that probably metamorphosed to form rock on unit 6 is called limestone. You can also use the sedimentary rock called dolostone. Both will be acceptable answers to this question.
