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inysia [295]
4 years ago
11

G 1) a2 + 3a – 40 = 0 . solving quadratic equations

Mathematics
1 answer:
QveST [7]4 years ago
5 0

Answer:

The solution set is {-8, 5}.

Step-by-step explanation:

a^2 + 3a – 40 = 0 .

We need 2 numbers whose product is  -40 and whose sum is +3.

They would be + 8 and - 5, so we have the factors:

(a + 8)(a - 5) = 0

Now either a + 8 = 0 or a - 5 = 0, so:

a = -8 or 5.

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What is the slope of (5, -3) and (8, -5) tell me how you got your answer
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To find the slope, you find the change in y-values over the change in x-values. 

Your first point is: (5,-3)
Your second point is (8, -5)
Your x-values are: 5 and 8
Your y-values are -3 and -5
The equation to find slope is: slope = (y2-y1)/(x2-x1)
       - The 2s and 1s indicate which point the values belong to, it makes sure               that you align the right x-value with its correct y-value. It doesn't matter               which point you assign as 1 or 2, as long as the values match
             - So, x-value 5 will match with y-value -3, and x-value 8 will match with                  y-value -5

Now you plug in out values :
slope = (y2-y1)/(x2-x1)
slope = (-5-(-3))/(8-5)
slope = (-2)/(3)
slope = -2/3


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