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3 years ago

G 1) a2 + 3a – 40 = 0 . solving quadratic equations

Mathematics

1 answer:

QveST [7]3 years ago

5 0

Answer:

The solution set is {-8, 5}.

Step-by-step explanation:

a^2 + 3a – 40 = 0 .

We need 2 numbers whose product is -40 and whose sum is +3.

They would be + 8 and - 5, so we have the factors:

(a + 8)(a - 5) = 0

Now either a + 8 = 0 or a - 5 = 0, so:

a = -8 or 5.

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2 years ago

The sum of two numbers is 24.The difference of their square is 144.what are the two numbers?

dimulka [17.4K]

Answer:

9 and 16

Step-by-step explanation:

let the two numbers are X and Y

X+Y=24

X^2-Y^2=144

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3 years ago

Find and equation for the line that passes through the points (-6,-4) and (4,4).

Ghella [55]

We have (x-4)/(-6-4) = (y-4)/(-4-4);
(x-4)/(-10) = (y-4)/(-8);
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3 years ago

Read 2 more answers

S= 4LW + 2WH; S=152, L=8, W=4. Find H

Katyanochek1 [597]

H is equal to 3. need the solution?

5 0

3 years ago

Find the percent of increase to the nearest whole from 12 to 20

ankoles [38]

Answer:

The answer is

Step-by-step explanation:

To find the percentage increase we use the formula

<h3> $Percentage \: change = \frac{change}{original \: \: quantity} \times 100\%$ </h3>

From the question

The original value = 12

To find the change we subtract the smaller value from the larger one

That's

Change = 20 - 12 = 8

So the percentage increase is

<h3> $\frac{8}{12} \times 100 \%\\ = \frac{2}{3} \times 100\% \\ = 66.67\%$ </h3>

We have the final answer as

$67\%$ to the nearest whole number

Hope this helps you

3 0

3 years ago