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3 years ago

G 1) a2 + 3a – 40 = 0 . solving quadratic equations

Mathematics

1 answer:

QveST [7]3 years ago

5 0

Answer:

The solution set is {-8, 5}.

Step-by-step explanation:

a^2 + 3a – 40 = 0 .

We need 2 numbers whose product is -40 and whose sum is +3.

They would be + 8 and - 5, so we have the factors:

(a + 8)(a - 5) = 0

Now either a + 8 = 0 or a - 5 = 0, so:

a = -8 or 5.

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