Find the midpoint of A and B where A has coordinates (2, 4) and B has coordinates (-3,-9).

Mathematics

1 answer:

Pavel [41]2 years ago

6 0

Answer:

x= -0.5

y= -2.5

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Simplify: 30 - 23 × 3

gogolik [260]

The answer to this question would be 39..here is why:

First you multiply 23 x 3..because multiplication or division always comes before addition or subtraction.

Second, you get the product from 23 x 3 which is 69..and you subtract 30 from that.

Last, after you do that you get an over all answer of 39..

Hope this helps!!

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2 years ago

Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

MAVERICK [17]

Answer:

The polynomial function is $x^{2} - 52$

Step-by-step explanation:

A polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ .

In this problem:

The roots are $x_{1} = 2\sqrt{13}$ and $x_{2} = -2\sqrt{13}$

Then

$(x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52$

The polynomial function is $x^{2} - 52$

8 0

2 years ago

Make x the subject! urgent help

Serhud [2]

Answer:

$x = \frac{n}{b - {t}^{2} }$

Step-by-step explanation:

I supposed that is a "n".

Steps as below:

${t}^{2} = b - \frac{n}{x} \\ b - \frac{n}{x} = {t}^{2} \\ - \frac{n}{x} = {t}^{2} - b \\ \frac{n}{x} = - ( {t}^{2} - b) \\ \frac{n}{x} = b - {t}^{2} \\ n = x(b - {t}^{2} ) \\ x(b - {t}^{2} ) = n \\ x = \frac{n}{b - {t}^{2} }$