Question

The picture below shows a container that Sue uses to freeze water: A cylinder is shown with base diameter of 4 centimeters and the height as 6 centimeters. What is the minimum number of identical containers that Sue would need to make 2,000 cm3 of ice? (Use π = 3.14.) (1 point) 12 18 27 7

Answer 1

Answer: 27

Step-by-step explanation:

Given: The height of the cylindrical container = 6 cm

Diameter of container = 4 cm

Then the radius of the container = $\frac{4}{2}=$2 cm

Now, the volume of the cylindrical container is given by :-

$\text{Volume}=\pi r^2 h\\\\\Rightarrow\text{Volume}=(3.14)(2)^2(6)=75.3982236862\approx75.4\ cm^3$

Now, the minimum number of identical containers that Sue would need to make 2,000 $cm^3$ of ice is given by:-

$\frac{2000}{75.4}=26.525198939\approx27$

Hence, the minimum number of identical containers that Sue would need to make 2,000 $cm^3$ of ice is 27.

Answer 2

Answer:

$27\ containers$

Step-by-step explanation:

step 1

Find the volume of one container (cylinder) is equal to

$V=\pi r^{2}h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=6\ cm$

substitute

$V=(3.14)(2^{2})(6)=75.36\ cm^{3}$

step 2

By proportion

Find the the minimum number of identical containers that Sue would need to make $2,000\ cm^{3}$ of ice

$\frac{1}{75.36}=\frac{x}{2,000}\\ \\x=2,000/75.36\\ \\x= 26.5\ containers$

Round to the nearest whole number

$26.5=27\ containers$