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KIM [24]
3 years ago
10

Branliest offered

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0

sqrt(1610) = 40.12 = -40.2

sqrt(680) = 36.08 = -36.08

sqrt(410) = 20.25 = -20.25

sqrt(27) = 5.20 = -5.20

 

is that supposed to be 025 or negative 25?

 the way the question is written

 the answer is C & D

 


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!!!!!!I WILL MARK AS BRAINLIEST!!! Please please please I need help with 15-17 PLEASE
docker41 [41]

Answer:

15.) BAD = 10. (Since AC is 8 and CD is 2 you'll add em together to form a right angle, and BAD is a right angle so therefore they are the same.)

16.) AB = 2. (CD is 2 so therefore AB is 2, Again same size...)

17.) BD = 8. (Same size as AC...)

8 0
4 years ago
the first n terms of the progression. The first term and common difference of an arithmetic progression are a and -2. respective
AlladinOne [14]

If <em>a</em> is the first term of an AP with common difference -2, then the first several terms are

<em>a</em>, <em>a</em> - 2, <em>a</em> - 4, <em>a</em> - 6, <em>a</em> - 8, …

with <em>n</em>-th term <em>a</em> - 2 (<em>n</em> - 1).

The sum of the first <em>n</em> terms is equal to the sum of the first 3<em>n</em> terms :

\displaystyle \sum_{i=1}^n (a-2(i-1)) = \sum_{i=1}^{3n} (a-2(i-1))

We have

\displaystyle \sum_{i=1}^N (a-2(i-1)) = (a+2)\sum_{i=1}^N - 2\sum_{i=1}^Ni = (a+2)N - 2\cdot\dfrac{N(N+1)}2 = (a+1)N-N^2

so that in the previous equation, the sums reduce to

(a+1)n-n^2 = (a+1)(3n)-(3n)^2

Solve for <em>a</em> :

(a+1)n-n^2 = (a+1)(3n)-(3n)^2 \\\\ (a+1)n-n^2 = (a+1)(3n)-9n^2 \\\\ 9n^2-n^2 = (a+1)(3n)-(a+1)n \\\\ 8n^2 = (a+1)(2n) \\\\ 4n = a+1 \\\\ \boxed{a=4n-1}

Now if <em>a</em> = 27, we have

27 = 4<em>n</em> - 1

28 = 4<em>n</em>

<em>n</em> = 7

as required.

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2 years ago
Who needs help with anything
Mumz [18]

Answer:

not me

Step-by-step explanation:

3 0
3 years ago
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Alvin is 13 years older than elga. the sum of their ages is 107. what is elga's age
frutty [35]
Alvin is 94 years old!
4 0
4 years ago
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You have a $50 bill. You and your friend ordered two cheese burgers for $4.25 each, two fries for $1.28 each, and two colas for
dusya [7]

Answer:

$32.13

Step-by-step explanation:

You and your friend ordered two cheese burgers for $4.25 each, two fries for $1.28 each, and two colas for $1.98 each.

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$50 bill. bill amount is 17.87

Amount received in change is

50-17.87=32.13

5 0
3 years ago
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