Answer:
There are 178 more boys in Barlow school as compared to Willow school.
Step-by-step explanation:
We are given the following in the question:
Barlow school:
Total number of students = 873
Number of boys =

Willow school:
Total number of students = 630
Number of girls =

Number of boys =
Total number of students - total number of girls

Thus, Barlow school has greater number of boys than Willow school.
Difference between the number of boys =

Thus, there are 178 more boys in Barlow school as compared to Willow school.
Answer:
$41,875
<u>Extra</u>
a. $17,250 [($780,000 – $90,000) ÷ 40]
b. $366,000 [$780,000 – ($17,250 × 24 yrs.)]
c. $29,600 [($366,000 – $70,000) ÷ 10 yrs.]
Step-by-step explanation:
Step 1: Determine the cost of the asset
Step 2: Subtract the estimated salvage value of the asset from the cost of the asset to get the total depreciable amount

Step 3: Determine the useful life of the asset

Step 4: Divide the sum of step (2) by the number arrived at in step (3) to get the annual depreciation amount

probability = (number of relevant possibilities)/(total number of possible outcomes)
p(woman chosen) = 26 / (24+26) = 13/25
Correct answer is (C)
Check the picture drawn
Consider the line segment AB,
let M be the midpoint of AB, so AM=MA
erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B
The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:
AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB
so PA=PB
Let x be the unknown number.
<span>7x + 668 </span><<span> 2000</span> => 7x plus 668 is less than 2000
where:
7x => x represents the number of cans to be collected in 7 days
668 is the number of cans already collected.
2000 is the target number of cans.
7x + 668 < 2000
- 668 -668
7x < 1332
÷7 ÷7
x < 190.30
or
x < 190
To check:
7x + 668 < 2000
7(190) + 668 < 2000
1330 + 668 < 2000
1998 < 2000