Answer:
first do 58-4 which is 54 then do 54/ 9 which is 6 so the number is 6
I assume the heights are 160 ft and 1480 ft.
The two heights are unknown, so we will use variable h to help solve the problem.
The shorter building, building A, has height h.
Since building A is shorter by 160 ft, then building B is taller by 160 ft, so the height of building B is h + 160.
Now we add our two heights to find the total height.
h + h + 160 is the total height.
We can write it as 2h + 160
We are told the total height is 1480 ft, so we let 2h + 160 equal 1480, and we have an equation.
2h + 160 = 1480
Subtract 160 from both sides
2h = 1320
Divide both sides by 2
h = 660
h + 160 = 820
Building A measures 660 ft.
building B measures 820 ft.
First factor the equation
(x-10)(x+2) = 0
Then solve for (x-10) and (x+2)
x=10
x=-2
Hii!
So I did this and I have A!
A: You cannot get the mean from the graph but you CAN get the third quartile!
B: To find the interquartile range (IQR) we subtract the third and first quartiles:
60-35 = 25
C: An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.
The answer to ( 1+7 )•3/6 is 4 and (7•3)•2/6 is 7