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3 years ago

Help me please thanks :)

Mathematics

1 answer:

Lunna [17]3 years ago

5 0

The median is 6
the mode is 7
and the mean is 22

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Help plz 15. and 16. math<br>explain and answer is on side already

Darina [25.2K]

15) x^2-2x-8=1/4x-1
x^2-2.25x-7=0
4x^2-9x-28=0
(x-4)(4x+7)=0
x-4= 0 or 4x+7=0
x=4 or x= -7/4=-1.75
16) answer hides in the f(x) equation
the trick is to think of the value that will make the (x-4) =0 and and the y value can be directly plugged off from the +c
therefore, ans is x=2 y= 4
(2,4)

5 0

4 years ago

The weight of gemstones, such as diamonds, rubies, and emeralds, is measured in carats. A carat is a unit of measure equal to 20

Alexxx [7]

We are told in the question that 1 carat is equal to 200 mg.

The Hope Diamond is 44.5 carats. Let's multiply the weight of 1 carat by 44.5 to get the weight of the Hope Diamond in mg:

$\frac{200mg}{1 carat}* \frac{44.5 carats}{1}=8,900 mg$

The total weight of the Hope Diamond is 8,900 mg. However the question asks for the weight in grams. There are 1000 mg in 1 gram, so let's divide the known weight of the Hope Diamond in mg by 1000 to get the weight converted to grams:

$\frac{8,900mg}{1000}=8.9grams$

Now we know that the weight of the Hope Diamond is equal to 8.9 grams.

8 0

3 years ago

Which statements are true about the curve? Check all

Shalnov [3]

Answer

The answer is 2,3,5

3 0

3 years ago

Chad had a dinner plate wth a radius of 16 inches. Whats is the circumference of the dinner plate?

Marat540 [252]

To find the circumference, you would use 2πr.

Answer:

2*π*16
=100.53in^2

6 0

3 years ago

Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the varia

Anon25 [30]

Answer:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property.

Step-by-step explanation:

Given the polynomial :

80b⁴ – 32b²c³ + 48b⁴c

The Greatest Common Factor (GCF) of the coefficients:

80, 32, 48

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80

32 : 1, 2, 4, 8, 16, and 32

48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

GCF = 16

b⁴, b², b⁴

b⁴ = b * b * b * b

b² = b * b

b⁴ = b * b * b * b

GCF = b*b = b²

GCF of c³ and c

c³ = c * c * c

c = c

GCF = c

We can see that David's GCF of the coefficients are all correct

From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect

In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)

6 0

3 years ago

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