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4vir4ik [10]
4 years ago
10

A rectangular box is x feet long and x feet wide. The volume of the box is (4x^8 + 3x^6) cubic ft. What polynomial represents th

e height of the box in feet?
Mathematics
2 answers:
inessss [21]4 years ago
8 0

Answer:

Hence, the height, in feet, of the rectangular box is given by the polynomial  h=4x^6+3x^4


Step-by-step explanation:

The volume of a rectangular box is given by the formula:

V=length*width*height


We are given V=4x^8+3x^6, length = x, and width = x , plugging these into the formula and figuring out height:

V=length*width*height\\4x^8+3x^6=(x)(x)(h)\\4x^8+3x^6=x^2h\\h=\frac{4x^8+3x^6}{x^2}\\h=\frac{x^2(4x^6+3x^4)}{x^2}\\h=4x^6+3x^4

Hence, the height, in feet, of the rectangular box is given by the polynomial  h=4x^6+3x^4


Rashid [163]4 years ago
3 0
h = \frac{4x^{8} + 3x^{6}}{x^{2}}
h = \frac{4x^{8}}{x^{2}} + \frac{3x^{6}}{x^{2}}
h = 4x^{6} + 3x^{4}
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So

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(4.28,6.48)
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maybe we are supposed to assume it starts at (0,0)
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first equation, minut a(4.28)^2 from both sides
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divide both sides by 4.28
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sub that for b in other equation

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15.04=a(12.61)^2+((6.48/4.28)-4.28a)(12.61)
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minus (81.7128/4.28) both sides
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to find b, subsitute to get
(6.48/4.28)-4.28((15.04-(81.7128/4.28))/(((12.61)^2-53.9708)))=b

if we aprox
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b≈1.6791118501845
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y=-0.038573167896199x²+1.6791118501845x
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