Answer:
X= -1 and x=5
Explanation:
Make it equal to zero
X-5=0
Then add five to both sides
X=5
For the other one do the same
X+1=0
Then subtract one on both sides
X=-1
Hope this helps!
To solve this problem we first call x = number of action figures, y = number of dolles. A system of two equations with two unknowns must be made to describe the problem. The system is the following:
(x + 1) + y = 13
1/2 * x = y.
Then solving the system we have that x = 8 and y = 4.
Since we know that the number of action figures is twice as many dolls plus one, then x = 8 + 1 = 9.
Thus,
dollos = 4
action figures = 9

but when you're trying to make a fraction into a decimal you have to divide the

from the

and that should

you a

Answer:
3:36 PM
Step-by-step explanation:
Let fraction (y) of the people that heard the rumor , the differential equation that is satisfied by the by y is,

Solving the differential equation,
![y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}](https://tex.z-dn.net/?f=y%28t%29%20%3D%20%5Cfrac%7By_%7Bo%7D%7D%7B%5By_%7Bo%7D%20%2B%20%281%20%2B%20y_%7Bo%7D%29e%5E%7B-kt%7D%5D%7D)
The total number of inhabitants of the town = 2000
The number of people that heard the rumor = 160
At 8 AM, let t = 0,

= 0.08
By noon, half of the town as heard the rumor.
Then,

Therefore,
![\frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B0.08%7D%7B%5B0.08%20%2B%20%281%20-%200.08%29e%5E%7B-4k%7D%5D%7D)
![\frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.08%7D%7B%5B0.08%20%2B%200.92e%5E%7B-4k%7D%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)




k ≈ 0.06106
Calculating time, t when y(t) = 90%
⇒ y(t) = 0.9
![\frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9](https://tex.z-dn.net/?f=%5Cfrac%7B0.08%7D%7B%5B0.08%20%2B%200.92e%5E%7B-0.06106t%7D%5D%7D%20%3D0.9)





t = 7.59 hours
⇒ 7 hours 36 minutes
From 8 A.M. plus 7 hours 36 minutes = 3:36 PM
At 3:36 PM will 90% of the population have heard the rumor
The points you are looking for are the midpoints of segments JL and JK.
J(-2, -1), K(4, -5), L(0, -5)
The midpoint of segment JL is
(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)
The midpoint of segment JK is
(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)
Answer: The coordinates are (-1, -3), (1, -3)