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3 years ago

If a pair of shoes cost $40 and they are on sale for 30% off how much would they be

Mathematics

1 answer:

yulyashka [42]3 years ago

6 0

multiply 40 by 30% to find the discount then subtract

40 * 0.30 = 12

40-12 = 28

they would cost $28

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The number of teams who entered in a 3-on-3 charity basketball tournament can be modeled by function T, where x is the number of

Svetradugi [14.3K]

Answer:

Option A:

$R(x)=20x^2+300x+1080$

Explanation:

The revenue, R(x) is the product of the number of teams who entered the tournament, T(x), times the entry fee paid by each team, F(x); then you can write:

$R(x)=T(x)\times F(x)$

Thus you must multiply the two functions (polynomials):

$R(x)=(4x+24)\times (5x+45)$

Use distributive property:

$R(x)=(4x+24)\times (5x+45)=(4x)(5x)+(4x)(45)+(24)(5x)+(24)(45)$

Simplify:

$R(x)=(4x)(5x)+(4x)(45)+(24)(5x)+(24)(45)=20x^2+180x+120x+1080$

Add like terms:

$R(x)=20x^2+180x+120x+1080=20x^2+300x+1080$

3 0

3 years ago

A collection of 77 quarters and dimes is worth $12.50. How many quarters are in the collection? PLS HELP ILL GIVE YOU BRAINLEST

mrs_skeptik [129]

Answer:

Step-by-step explanation:

77 quarters and dimes

q + d = 77

subtract q from both sides

d = 77 - q

---------------------------

A collection of quarters and dimes is worth $12.50 (1250 cents)

25q + 10d = 1250

substitute for d

25q + 10(77 - q) = 1250

distribute

25q + 770 - 10q = 1250

Combine like terms

15q + 770 = 1250

subtract 770 from both sides

15q = 480

divide both sides by 15

q = 32

3 0

3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$