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lara [203]
3 years ago
11

How do you solve 2 log x = log 64?

Mathematics
2 answers:
irinina [24]3 years ago
7 0
2\log { x } =\log { 64 } \\ \\ \log { \left( { x }^{ 2 } \right)  } =\log { \left( { 8 }^{ 2 } \right)  } \\ \\ { x }^{ 2 }={ 8 }^{ 2 }\\ \\ x={ \left( { 8 }^{ 2 } \right)  }^{ \frac { 1 }{ 2 }  }\\ \\ x=8
kenny6666 [7]3 years ago
6 0
x>0 \\ \\
2 \log x= \log 64 \\
\log x^2=\log 64 \\
x^2=64 \\
x=-8 \ \lor \ x=8 \ and \ x>0 \\
\boxed{x=8}

Used formulas:
n \log_a b=\log_a b^n \\
\log_a b, b>0
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Answer:

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Step-by-step explanation:

Harmonic mean of  x and y = 2xy/( x + y )

<u>Formulate a conjecture about their relative sizes </u>

we will achieve this by computing harmonic and geometric means

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attached below is the proof

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2 years ago
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Viktor [21]

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Therefore, Option A is the correct answer.

8 0
3 years ago
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Step-by-step explanation:


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