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lara [203]
3 years ago
11

How do you solve 2 log x = log 64?

Mathematics
2 answers:
irinina [24]3 years ago
7 0
2\log { x } =\log { 64 } \\ \\ \log { \left( { x }^{ 2 } \right)  } =\log { \left( { 8 }^{ 2 } \right)  } \\ \\ { x }^{ 2 }={ 8 }^{ 2 }\\ \\ x={ \left( { 8 }^{ 2 } \right)  }^{ \frac { 1 }{ 2 }  }\\ \\ x=8
kenny6666 [7]3 years ago
6 0
x>0 \\ \\
2 \log x= \log 64 \\
\log x^2=\log 64 \\
x^2=64 \\
x=-8 \ \lor \ x=8 \ and \ x>0 \\
\boxed{x=8}

Used formulas:
n \log_a b=\log_a b^n \\
\log_a b, b>0
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Write an equivalent expression by distributing the "-−" sign outside the parentheses:
charle [14.2K]

Answer:

6.6a+6b-7.1

Step-by-step explanation:

-(-6.6a-6b)-7.1\\\\=-(-6.6a)-(-6b)-7.1\\\\=6.6a+6b-7.1

7 0
2 years ago
There are 24 students in homeroom 218. 7/12 of the students are girls. How many girls are in homeroom 218?
hichkok12 [17]

There are 14 girls in HR 218 because 24/12 is 2, meaning that the ratio needs to be multiplied by 2/2 in order to figure out what 7/12 is.  7/12*2/2 is 14/24, therefore there are 14 girls in HR 218.

8 0
3 years ago
1/2x+2/3=1/3-3/2 What does x equal and can you show me the steps?
Irina18 [472]
X/2+2/3 = 2+3(-3)/3*2

3x+2*2=2*3 = 2-3*3/3*2

3x+4/2*3 = 2-9/3*2

3x+4=-7

(3x+4)+(-4)=-7-4

3x=-11

3x/3=-11/3

x=-11/3

hope  this helps!

3 0
3 years ago
Find all real values of $t$ that satisfy the equation $t^2 = 324$. the answer is 18.
zhuklara [117]

Answer:

the real values that satisfy the equation are:

t=18,\:t=-18

Step-by-step explanation:

Given the equation

$t² = 324$

Let us solve the equation

t^2=324

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

t=\sqrt{324},\:t=-\sqrt{324}

as

\sqrt{324}=18-\sqrt{324}=-18

so

t=18,\:t=-18

Thus, the real values that satisfy the equation are:

t=18,\:t=-18

4 0
3 years ago
Read 2 more answers
There are 4 different methods you could use to solve a quadratic equation that would depending upon the actual equation. They ar
lana66690 [7]

Answer:

Part A: x^2 + 6x + 8 = 0 use the factoring the equation method

Part A: x^2 + 6x + 8 = 0 use the quadratic formula

Step-by-step explanation:

Part A;

The equation is  x^2 + 6x + 8 = 0 , looking at this quadratic expression, you notice it is written in a quadratic equation standard form  of ax^2+bx+c=0. Additionally, you notice that can find what multiplied to get the quadratic equation,factor.You can identify two numbers that multiply to get ac and add to give b.In this question;

a=1,b=6,c=8

ac=8

The numbers are 4 and 2. Factoring the equation method will give;

x²+6x+8=0

x²+4x+2x+8=0

x(x+4)+2(x+4)=0

(x+2)+(x+4)=x²+6x+8

x+2=0, x=-2  and x+4=0, x=-4

Part B

The quadratic equation is ;

x²+6x-11=0

You notice that there are no factors that multiply direct to get the quadratic equation like in part 1. When you observe, a=1, b=6 and c=-11

ac=1×-11=-11 and b=6 .You notice there are no factors that multiply to give -11 and add to get 6, hence the factorizing the equation method can not be used.However, you can apply the quadratic formula that requires coefficients. You have a=1, b=c and c=-11 as the coefficients to use in the quadratic formula.

8 0
3 years ago
Read 2 more answers
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