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Galina-37 [17]
3 years ago
15

Representatives running for office are handing out items to voters. Every 8th voter gets a button. Every 10th voter gets a stick

er.
Which voter is the first to receive both items?

Drag and drop the answer into the box to complete the statement.


The th voter receives both items.

a 4th
b 5th
c 8th
d 9th
e 10th
f 24th
g 40th
h 48th
i 80th
Mathematics
1 answer:
seropon [69]3 years ago
3 0
I)
Every 8.th voter gets a button:

so a sequence of the voters who receive a button is:

8, 16, 24, 32, ....   that is  8*1, 8*2, 8*3, 8*4, .... in general: 8k for some integer k  

ii)

Every 10.th voter gets a sticker, so the voters who receive stickers are the :

10, 20, 30, 40, .... voters    that is 10*1, 10*2, 10*3, 10*4... in general 10t

for some integer t


iii) what we are looking for is the first number which is 8k and 10t at the same time.

8k=2*2*2k, 
10t=2*5t

Thus this number must be divisible by 2*2*2*5*{some positive integer}

the smallest number is when the positive integer is 1, thus the number is 

2*2*2*5=8*5=40


Answer: g. the 40th
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Answer:

y=1x+-1

Step-by-step explanation:

y=mx+b

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b=y-intercept form which is -1 because that is where the line meets the y axis

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Express jenny’s age in terms of a if jenny is three years less than half of Anne’s age.
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Answer:

If Anne’s age is represented by the variable a then express Jenny’s age in terms of a if Jenny is three years less than half of Anne’s age

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Inequalities? the product of 11 and a number is less than 53 i'm confused on how to write it out
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3 0
2 years ago
Please see attachment
Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }  

Step-by-step explanation:

<u>Step(i)</u>:-

Given function

                       f(x) = \frac{-x}{2x^{2} +1}     ...(i)

Differentiating equation (i) with respective to 'x'

                     f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2}  }   ...(ii)

                    f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  }

Equating Zero

                   f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                 \frac{2x^{2}-1}{(2x^{2}+1)^{2}  } = 0

                2 x^{2}-1 = 0

               2 x^{2} = 1

             x^{2}  = \frac{1}{2}

             x = \frac{-1}{\sqrt{2} }  , x = \frac{1}{\sqrt{2} }

<u><em>Step(ii):</em></u>-

Again Differentiating equation (ii) with respective to 'x'

f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4}  }

put

      x = \frac{1}{\sqrt{2} }

f^{ll} (x) > 0

The absolute minimum value at   x = \frac{1}{\sqrt{2} }

<u><em>Step(iii):</em></u>-

The value of absolute minimum value

                         f(x) = \frac{-x}{2x^{2} +1}

                       f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}

         on calculation we get

The value of absolute minimum value = - 0.3536      

<u><em>Final answer</em></u>:-

a) The value of absolute minimum value = - 0.3536  

b) which is attained at   x = \frac{1}{\sqrt{2} }    

3 0
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antoniya [11.8K]

Answer:

 i'll explain it to you

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