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valentinak56 [21]
3 years ago
14

How do I solve this?

Mathematics
1 answer:
il63 [147K]3 years ago
5 0
Well inverse means that it is the opposite, so what is the opposite of that?
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Can someone please help me answer this?
ozzi
For this problem i got

7 0
3 years ago
The jogging track is of a mile long. If Ashley jogged around it 4 times, how far did she run?
matrenka [14]

Answer: 4 miles

Step-by-step explanation:

If Ashley ran 1 mile 4 times, she ran 1+1+1+1, or 1*4, or 4 miles.

<em>Hope it helps <3</em>

5 0
3 years ago
Complete the table for the given rule.<br><br><br>rule: y=x-4<br><br><br>x:? y:6 0 4
Triss [41]

Answer:

10, 4, 8

Step-by-step explanation:

10 - 4 = 6

4 - 4 = 0

8 - 4 = 4

3 0
3 years ago
Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
  •  4
  • 5
  • 0
  • 1.5sin(3t)
  • 1
  •  2.5

Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
3 years ago
Given the function h(x), determine the functions which correctly decompose h(x) into component functions f(x) and g(x) so that h
nataly862011 [7]

\text{Hi there! :)}

\large\boxed{g(x) = 7x + 2\text{ , } f(x) = \sqrt{x}  - 10}

\text{h(x) = f(g(x)), so determine what g(x) was substituted into f(x):}\\\\\text{Given the equation } h(x) = \sqrt{7x +2}- 10:\\\\\text{In the part of the equation with a variable, we see that "7x + 2" is in a square root:}

\text{Therefore, we can say that g(x) = 7x + 2:}\\\\\text{If h(x) = f(7x + 2), then f(x) must be:}\\\\f(x) = \sqrt{x} - 10

\text{The respective functions would be:}\\\\g(x) = 7x + 2\\\\f(x) = \sqrt{x}  - 10

7 0
3 years ago
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