Hi there
The formula of the future value of annuity ordinary is
Fv=pmt [(1+r/k)^(kn)-1)÷(r/k)]
Fv future value?
PMT quarterly payment 600
R interest rate 0.059
K compounded quarterly 4
N time 6 years
Fv=600×(((1+0.059÷4)^(4×6))
÷(0.059÷4))=57,806.50
Hope it helps
You are given the unknown number which has a quotient of 3 and a
remainder of 28. This means that 3 is the whole number from the division of the
unknown number and 43 and 28 is the decimal, 3.28. Also, the number is divided
by 43 too. Let us denote n as the number so we have n/43. Then equate the n/43
to 3.28.
n/43 = 3.28
n = 43 (3.28)
n = 141.04
<span>The number is 141. 04</span>
Answer:
m<1 = 162° , m<2 = 18°
Step-by-step explanation:
m<1 + m<2 = 180°
6x + x - 9 = 180°
7x - 9 = 180°
7x = 180 + 9
x = 27
Answer:
n=206
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
Solution to the problem
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by and . And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that , we can use as prior estimate of p 0.5, since we don't have any other info provided, and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
And replacing into equation (b) the values from part a we got:
And rounded up we have that n=206