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jasenka [17]
3 years ago
10

The membership in the math club at Rogers Junior High increased by 6% from last year to this year. The president of the math clu

b used the following expression to find the number of members in the club this year. m + m(0.06) Which of the following is another expression that could be used to get the same results?
A. 106m
B. m + 1.06
C. 1.06m
D. m + 6
Mathematics
1 answer:
Anon25 [30]3 years ago
7 0
The answer would be  B.

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IgorC [24]

A standard die has numbers = 1,2,3,4,5 and 6

Total outcomes = 6

P = Number of outcomes/Total Outcomes

Even and less than 4 = 1,2,3,4 and 6

P = 5/6

Answered by GauthMath if you like please click thanks and comment thanks

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What is the height of the tree to the nearest foot?
goblinko [34]
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You use Sin60degX40ft
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I need help with 44 and 45
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44 is F) 32 square feet

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5 0
3 years ago
The probability that a certain kind of component will survive a shock test is 3/4. Find the probability that exactly 2 of the ne
Marina86 [1]

Answer:

Therefore the required probability is =\frac{27}{128}

Step-by-step explanation:

The probability of success is \frac{3}{4}

The number of trial = 4

X= the items survive out of 4

P(x=r)=^nC_rq^{n-r}p^r        p =the probability of success and q = the probability failure.

p=\frac{3}{4}     and q=(1-\frac{3}{4})=\frac{1}{4}

\therefore P(X=2)=^4C_2(\frac{1}{4} )^2(\frac{3}{4} )^2

                  =\frac{4!}{2!2!} (\frac{1}{16} )(\frac{9}{16} )

                  =\frac{27}{128}

Therefore the required probability is =\frac{27}{128}

3 0
4 years ago
Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y
mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Step-by-step explanation:

Given the data in the question;

y = y = e^{(x - 1 ), y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = y = e_2}^{(x - 1 )_, y = 0

Volume = \pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx

Volume = \pi \int\limits^2_1 ( e^{x-1)^2  dx

Volume = \pi \int\limits^2_1 e^{2x-2}dx

Volume = \frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx

Volume = \frac{\pi }{e^2}  [\frac{e^{2x}}{2}]^2_1

Volume = \frac{\pi }{2e^2}  [e^4 - e^2 ]  

Volume = \frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

   

3 0
3 years ago
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