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s2008m [1.1K]
3 years ago
5

Find the domain and the range of the given relation {(2,-8), (9,5), (-9,6), (6,-9)}

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

what relation I don't see anything

Step-by-step explanation:

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Simplify the expression.<br> 28 + 4<br> 2<br> A. 9<br> B. 11<br> C. 16<br> D. 22
padilas [110]

Answer:

C) 16

Step-by-step explanation:

\dfrac{28+4}{2}=\dfrac{32}{2}=16

8 0
2 years ago
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A pole that is 3.4 m tall casts a shadow that is 1.54 m long. At the same time, a nearby building casts a shadow that is 35.75 m
inna [77]

Answer:

The building would be 78.92 meters tall.

Step-by-step explanation:

If the shodow of a 3.4m tall pole is 1.54m tall, and you have the shadow's height, then you make a cross, multiply-divide ratio table.

5 0
2 years ago
A manager bought 12 pounds of peanuts for $30. He wants to mix $5 per pound cashews with the peanuts to get a batch of mixed nut
seraphim [82]

Answer:

18 pounds of cashews are needed.

Step-by-step explanation:

Given;

A manager bought 12 pounds of peanuts for $30.

Price of peanut per pound P = $30/12 = $2.5

Price of cashew per pound C = $5

Price of mixed nut per pound M = $4

Let x represent the proportion of peanut in the mixed nut.

The proportion of cashew will then be y = (1-x), so;

xP + (1-x)C = M

Substituting the values;

x(2.5) + (1-x)5 = 4

2.5x + 5 -5x = 4

2.5x - 5x = 4 -5

-2.5x = -1

x = 1/2.5 = 0.4

Proportion of cashew is;

y = 1-x = 1-0.4 = 0.6

For 12 pounds of peanut the corresponding pounds of cashew needed is;

A = 12/x × y

A = 12/0.4 × 0.6 = 18 pounds

18 pounds of cashews are needed.

4 0
3 years ago
A metal bar has the D of 7.9 g/mL. If the volume of the bar is 500mL, what is the mass in kg?​
morpeh [17]

Answer:

It will be 0.5kg cuz kg and liters are same

8 0
3 years ago
A study of class attendance and grades among first-year students at a state university showed that, in general, students who mis
ratelena [41]

Answer:

the numerical value of the correlation between percent of classes attended and grade index is r = 0.4

Step-by-step explanation:

Given the data in the question;

we know that;

the coefficient of determination is r²

while the correlation coefficient is defined as r = √(r²)

The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.

Now, given that class attendance explained 16% of the variation in grade index among the students.

so

coefficient of determination is r² = 16%

The correlation coefficient between percent of classes attended and grade index will be;

r = √(r²)

r = √( 16% )

r = √( 0.16 )

r = 0.4  

Therefore,  the numerical value of the correlation between percent of classes attended and grade index is r = 0.4

3 0
3 years ago
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