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3 years ago

A 30-foot pole is stabilized by a wire attached to the ground 10 feet from the base of the pole. how long is the wire?

Mathematics

1 answer:

Leya [2.2K]3 years ago

6 0

Answer:

height of the pole is 16.1

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Is 1.36¯¯¯¯ rational or irational

fenix001 [56]

Answer:

rational

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help!! Select the correct answer??

VladimirAG [237]

The quotient is : 5x-12+(25)/(x+3)

The remainder is : 25

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3 years ago

Which dimensions can create more than one triangle? A. Three angles measuring 75 degrees, 45 degrees, and 60 degrees. B. Three s

AnnyKZ [126]

The answer is C

Because the sum of the angles are not up to 180

which makes way for other angles.

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3 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

3 years ago

A 0.3 kilogram softball is thrown toward a catcher's mitt. the ball is accelerating at a rate of 8 meters per second squared wit

schepotkina [342]

Force = mass * acceleration
Force = 0.3 km * 8m = 2.4 N
I got a different answer from a,b,c

4 0

3 years ago