Answer:
$y=(7/2)x+20$
Step-by-step explanation:
SInce the gradient of the first line is $-2/7$ then the gradien of the perpendicular line is $7/2$.
Therefore by the point slope formula the line that we are looking for is
$y-6=(7/2)(x+4)$
$y=(7/2)x + 20$
D. X=130 but im not sure if this is correct
Sin theta = 8/17 and theta is in the second quadrant. Find sin(2theta),cos(2theta),tan(2theta) exactly sin(2theta) cos(2theta) tan(2theta) sin(2theta) would it be 2 x (8/17) cos(2theta) would be 2 x (15/17) tan(2theta) would be 2 x (8/17 divided by 15/17) is this correct?
The 3rd one: "Converse of the Same-Side Interior Angles Postulate"