3 years ago

Factorise fully 72-2y^2

Mathematics

2 answers:

KiRa [710]3 years ago

7 0

Answer: 2(y + 6)(-y + 6)

Step-by-step explanation: Factor 72 - 2y^2

-2y^2 + 72

= 2(y + 6)(-y + 6)

attashe74 [19]3 years ago

6 0

Answer:

$-2\left(y+6\right)\left(y-6\right)$

Step-by-step explanation:

$72-2y^2$

$-2y^2+72$

Factor out GCF.

$2(-y^2+36)$

Apply difference of two squares formula.

$-2\left(y+6\right)\left(y-6\right)$

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What is an equation of the line that passes through the points (0, 3) and (5,-3)?

Arisa [49]

Answer:

The equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .

Step-by-step explanation:

From Analytical Geometry we must remember that a line can be formed after knowing two distinct points on Cartesian plane. The equation of the line is described below:

$y = m\cdot x + b$ (Eq. 1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $(x_{1},y_{1}) = (0,3)$ and $(x_{2},y_{2})=(5,-3)$ , the following system of linear equations is constructed:

$b = 3$ (Eq. 2)

$5\cdot m + b = -3$ (Eq. 3)

The solution of the system is: $b = 3$ , $m = -\frac{6}{5}$ . Hence, we get that equation of the line that passes through the points (0, 3) and (5, -3) is $y = -\frac{6}{5}\cdot x +3$ .