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Dvinal [7]
3 years ago
14

Which function is not a translation of f(x)=x2+17? f(x)=−x2−17 f(x)=(x−4)2 f(x)=(x+12)2 f(x)=(x−4)2+17

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0
F(x) = -x²-17 is not a translation.

A translation of this graph would either have something added to/subtracted from the end of the function (the c value) or something added or subtracted to x before it is squared.  f(x) = -x²-17 is a reflection, as the coefficient of x² is negative.

Every other choice has something either added to or subtracted from either x before it is squared or from the end.
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Rewrite the expression as an algebraic expression in x. <br> cos(tan−1 x)
zhenek [66]
It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).

So, use "arctan x" instead.

Then the problem becomes:  "differentiate cos (arctan x)."

You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:

(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]

7 0
3 years ago
What would x be in px + 3 = k
yulyashka [42]

Answer:

Step-by-step explanation:

k=3

6 0
3 years ago
What is the surface area of this composite figure?
faust18 [17]

Answer:

<h2>          294 cm²</h2>

Step-by-step explanation:

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4 0
2 years ago
What is the length of the hypotenuse of the triangle below?​
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

So here we have a 45-45-90 triangle.

This a special right triangle were the sides across from the 45 degree angles can be considered x, while the hypotenuse is two square roots of x.

Here since we have the sides across from the 45 degree angle we can conclude that x = 9\sqrt{2}

So if we wanted the hypotenuse we would just plug in this value of x like so:

hyp = x\sqrt{2} \\

hyp = (9\sqrt{2})(\sqrt{2})

hyp = 9(2)\\

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Therefore the hypotenuse is 18.

3 0
3 years ago
Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
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