2 years ago

Please help me with this I will mark you brainliest

Mathematics

1 answer:

Zinaida [17]2 years ago

7 0

AC=4.26 cm

Hope this helps you

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1/3

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Step-by-step explanation:

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$x^2-4x+3$

$63\ \text{sq. units}$

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$A=lw\\\Rightarrow A=\dfrac{x^2-x-6}{x-5}\times\dfrac{x^2-6x+5}{x+2}\\\Rightarrow A=\dfrac{x^2-3x+2x-6}{x-5}\times\dfrac{x^2-5x-1x+5}{x+2}\\\Rightarrow A=\dfrac{(x-3)(x+2)}{x-5}\times\dfrac{(x-5)(x-1)}{x+2}\\\Rightarrow A=(x-3)(x-1)\\\Rightarrow A=x^2-4x+3$