Answer:
Step-by-step explanation:
Circumference = 6π
θ = 8/3 = 2.7 radians
Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
6x-12
Combine 2x and 4x = 6x
Combine -17 and 5 = -12
1) <ABC
2) 120
3) 22
4) <GFH
5) 29
6) 90
7) 45
8) 63
9) 45
10) 110