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3 years ago

What are the solutions of the equation?

Mathematics

1 answer:

Margaret [11]3 years ago

4 0

Answer:

Option (C) is correct.

The solution of the quadratic equation $12x^2+11x-5=0$ is $x=\frac{1}{3}$ and $x=\frac{-5}{4}$

Step-by-step explanation:

Consider the given quadratic equation $12x^2+11x-5=0$

We can solve the quadratic equation using middle term splitting method,

11x can be written as 15x-4x , we get,

$\Rightarrow 12x^2+11x-5=0$

$\Rightarrow12x^2+15x-4x-5=0$

Taking terms common, we get,

$\Rightarrow3x(4x+5)-1(4x+5)=0$

Thus, $\Rightarrow (3x-1)(4x+5)=0$

Thus, we get $\Rightarrow (3x-1)=0$ or $\Rightarrow (4x+5)=0$

this gives $\Rightarrow x=\frac{1}{3}$ or $\Rightarrow x=\frac{-5}{4}$

Thus, the solution of the quadratic equation $12x^2+11x-5=0$ is $x=\frac{1}{3}$ and $x=\frac{-5}{4}$

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a cooper wire was 240 meters long. after 60 meters was cut off, it was double the length of a steel wire. how much longer was th

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The copper wire was 150 meters longer than the steel wire. You take 240-60 and get 180. You can then divide that number by 2 to figure out how long the steel wire was to get 90. From there, subtract the 90 by the original 240 and you’ll get 150.

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Alex spent 25% of his money on a sport drink .then he spent 25% of the remaining money on a trial mix .he had 9$ dollar left .ho

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A player tosses a die 6 times.If gets a number 6 Atleast two times he wins 2 dollars ,otherwise he looses 1 dollar.. Find the ex

swat32

Answer:

$E(x)=-0.2101$

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

$E(x)=x_1*p(x_1)+x_2*p(x_2)$

Where $x_1$ and $x_2$ are the values that the variable can take and $p(x_1)$ and $p(x_2)$ are their respective probabilities.

So, a player can win 2 dollars or looses 1 dollar, it means that $x_1$ is equal to 2 and $x_2$ is equal to -1.

Then, we need to calculated the probability that the player win 2 dollars and the probability that the player loses 1 dollar.

If there are n identical and independent events with a probability p of success and a probability (1-p) of fail, the probability that a events from the n are success are equal to:

$P(a)=nCa*p^a*(1-p)^{n-a}$

Where $nCa=\frac{n!}{a!(n-a)!}$

So, in this case, n is number of times that the player tosses a die and p is the probability to get a 6. n is equal to 6 and p is equal to 1/6.

Therefore, the probability $p(x_1)$ that a player get at least two times number 6, is calculated as:

$p(x_1)=P(x\geq2)=1-P(0)-P(1) \\\\P(0) =6C0*(1/6)^{0}*(5/6)^{6}=0.3349\\P(1)=6C1*(1/6)^{1}*(5/6)^{5}=0.4018\\\\p(x_1)=1-0.3349-0.4018\\p(x_1)=0.2633$

On the other hand, the probability $p(x_2)$ that a player don't get at least two times number 6, is calculated as:

$p(x_2)=1-p(x_1)=1-0.2633=0.7367$

Finally, the expected value of the amount that the player wins is:

$E(x)=x_1*p(x_1)+x_2*p(x_2)\\E(x)=2*(0.2633)+ (-1)*0.7367\\E(x)=-0.2101$

It means that he can expect to loses 0.2101 dollars.

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An acute triangle is isosceles. Is this statement true? pls explain

solniwko [45]

Answer:

I hope this helps:)

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3 years ago

23) A backyard has a perimeter of 144m.

german

A) 144/4 = 36 metres per side
b) 18*3 = 54
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dimensions would be 54 by 18

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