Question

What are the solutions of the equation?

Answer 1

Answer:

Option (C) is correct.

The solution of the quadratic equation $12x^2+11x-5=0$  is $x=\frac{1}{3}$ and $x=\frac{-5}{4}$

Step-by-step explanation:

Consider the given quadratic equation $12x^2+11x-5=0$

We can solve the quadratic equation using middle term splitting method,

11x can be written as 15x-4x , we get,

$\Rightarrow 12x^2+11x-5=0$

$\Rightarrow12x^2+15x-4x-5=0$

Taking terms common, we get,

$\Rightarrow3x(4x+5)-1(4x+5)=0$

Thus, $\Rightarrow (3x-1)(4x+5)=0$

Thus, we get $\Rightarrow (3x-1)=0$  or $\Rightarrow (4x+5)=0$

this gives $\Rightarrow x=\frac{1}{3}$ or $\Rightarrow x=\frac{-5}{4}$

Thus, the solution of the quadratic equation $12x^2+11x-5=0$  is $x=\frac{1}{3}$ and $x=\frac{-5}{4}$