Answer:
11.45mm^2
Step-by-step explanation:
Given data
Circumference= 12mm
The expression for the circumference is
C= 2πr
12= 2*3.14*r
12= 6.28r
r= 12/6.28
r= 1.91mm
Hence the area of each small circle is
A= πr^2
A= 3.14*1.91^2
A= 3.14*3.6481
A=11.45mm^2
P = 300/V
Because in order to isolate P, you have to divide V on both sides.
<span>x = 9
Since ZP bisects â OZQ, that means that the measurements for â OZP and â PZQ are the same. So create an equation with their respective values set to each other.
8x - 9 = 5x + 18
Now solve for x
8x - 9 = 5x + 18
Subtract 5x from both sides
3x - 9 = 18
Add 9 to both sides
3x = 27
Divide both sides by 3
x = 9</span>
Answer:
0.27 repeating.
Step-by-step explanation:
So to solve this we just have to use division.
1 clearly doesnt go into 3 at least one time, so we can add a decimal point and add a 0 to make it 30.
11 goes into 30 2 times, so we have:
0.2
and 30-22=8
So we can add another 0 and make it 80.
Then 11 goes into 80 7 times. So we have:
0.27
and 80-77=3
So again, add the 0, we have 30.
11 goes into 30 2 times, so:
0.272
and 30-22=8
Add another 0 we get 80.
11 goes into 80 7 times.
So finally, we have:
0.2727.
This is a repeating decimal.
This can be shown as:
0.<u>27</u>
So this is your answer!
I was a bit confused with which one it was on your answer key, but knowing that it is 0.<u>27</u> I am guessing you can chose!
Hope this helps!
The answer is C. 6x-24.
<span>Distribute the 6 to both terms in parentheses: 6(x)-6(4) </span>
<span>Final Answer:6x-24</span>
