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3 years ago

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The equation shown has a missing value. -2(2x-?)+1=17-4x. For what missing value(s), if any, does the equation have exactly one

solution?For what missing value(s), if any does the equation have no solution?

1 answer:

faust18 [17]3 years ago

8 0

Answer:

(4x-16)+1

Step-by-step explanation:

ABOVE^

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Please help with this

Dafna1 [17]

Answer:

A

Step-by-step explanation:

● first one:

The diagonals of a rhombus are perpendicular to each others wich means that they form four right angles.

STP is one of them so this statement is true.

● second one:

If ST and PT were equal this would be a square not a rhombus.

● third one:

If SPQ was a right angle, this woukd be a square.

● fourth one:

Again if the diagonals SQ and PR were equal, this would be a square.

5 0

3 years ago

Maggie has 3 quarters, Elizabeth has 5 quarters, and Johnny has 7 quarters. If q represents $0.25, which of the following expres

miskamm [114]

Answer:

3 + 5 + 7 = 15

they have 15 quarters altogether so answer is 15q

5 0

3 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

2 years ago

Hurry someone please answer plsss<br> Find the midpoint of each line segment.

djverab [1.8K]

Answer:

2.5

Step-by-step explanation:

you can use pythag theorem and divide c by two:

-3^2+4^2=c^2

9+16= 25

c=5

however, 5/2=2.5

4 0

2 years ago

Colin buys a car for £42800.

guapka [62]

Answer:

Principal=₹42800

Rate of interest=5% but 2 years so multiply by 2 =5×2=10%

Time=2 years

Simple interest=42800×10×2/100= ₹8560

Amount=42800+8560=Rs51360

The answer is ₹ 51360

Please make me as brainliest

Step-by-step explanation:

8 0

2 years ago