Ask question

Ask question

All categories

3 years ago

11

In which structure of the female reproductive system is a zygote typically found?

2 answers:

Thepotemich [5.8K]3 years ago

3 0

It's A. Fallopian Tube. The ovaries create the egg and the fallopian tubes hold the zygote until it is fertilized, then transfer it to the uterus.

BARSIC [14]3 years ago

3 0

Zygote is formed in the Fallopian tube.

Once in a month the egg is released from the ovary to the fallopian tube where the sperm of male is present for the process of fertilization which results in formation of zygote. Zygote remains in the fallopian tube for the next three to four days. Then it travels to the uterus for the implantation where the growth and nourishment of embryo takes place.

You might be interested in

In DNA, only the _____ varies from one nucleotide to another.

kotykmax [81]

Only the bases varies from one nucleotide to another.

6 0

3 years ago

Read 2 more answers

If you view a full moon on february 3rd when will you view the next 1st quarter moon?

Anarel [89]

Answer: 29.5 days

Hi, i got this answer in my class cause we actually did the same thing.

5 0

2 years ago

Read 2 more answers

Part B Based on the information in the article, do you think the human body has one type of sensory receptor or several types of

bezimeni [28]

Several is the answer

5 0

2 years ago

Read 2 more answers

g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time

Elenna [48]

Answer:

a. 8.1 milligrams

b. 40.07 hours

c. 8.859 milligrams

Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

$A_{t}=10e^{-0.0173t}$

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

$A_{12}=10e^{-0.0173\times12}$

$A_{12}=10e^{-0.2076}$

= 10×0.81253

= 8.1 milligrams

b. In this part we have to calculate the time when A(t) = 5 milligrams

$5=10e^{-0.0173\timest}$

$\frac{5}{10}=e^{-0.0173t}$

0.5 = $e^{-0.0173t}$

Now we take natural log on both the sides of the equation.

ln(0.5) = ln( $e^{-0.0173t})$

-0.69314 = -0.0173t

t = $\frac{0.69314}{0.0173}$

t = 40.0658

≈ 40.07 hours

c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

$A_{7}=10e^{-0.0173\times7}$

$A_{7}=10e^{-0.1211}$

= 10×0.8859

= 8.859 milligrams

6 0

3 years ago

What is a question that might be investigated by an environmntal scientist

insens350 [35]

Where is the natural habitat at

5 0

3 years ago

Read 2 more answers