Answer:
The range for Problem 18 is
The range for problem 19 is
Step-by-step explanation:
To find the range you subtract the smallest value from the largest value. In problem 18 the largest value was 17.6 and the smallest was 1.5.
In problem 19 the largest value was 181 and the smallest was 14
Answer: b. 14ft
Step-by-step explanation:
In the rectangle, the opposite sides are equal. The diagonal divides the rectangle into two equal right angle triangles. The diagonal represents the hypotenuse of both right angle triangles. The length and width represents the opposite and adjacent sides of the right angle triangles.
To determine the length, L of the rectangle, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Therefore,
16² = L² + 7²
256 = L² + 49
L² = 256 - 49 = 207
L = √207
L = 14.38
the closest to the length of this rectangle in feet is
14ft
Answer:
As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).
Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.
Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.
So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!
Step-by-step explanation:
