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ipn [44]
3 years ago
6

Determine which functions have two real number zeros by calculating the discriminant, b2 – 4ac. Check all that apply.

Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer with Step-by-step explanation:

We are given that

Discriminant, D=b^2-4ac

When D\geq 0

Then, the function have two  real zeroes.

1.f(x)=x^2+6x+8

By comparing withe general quadratic equation

ax^2+bx+c=0

We get a=1,b=6,c=8

Using the discriminant formula

D=(6)^2-4(1)(8)=36-32=4>0

Hence, function have two real zeroes.

2.g(x)=x^2+4x+8

D=(4)^2-4(1)(8)=16-32

D=-16

Hence, the function have no two real number zeroes.

3.h(x)=x^2-12x+32

D=(-12)^2-4(1)(32)=144-128=16

D>0

Hence, function have two real zeroes.

4.k(x)=x^2+4x-1

D=(4)^2-4(1)(-1)=16+4=20

D>0

Hence, function have two real zeroes.

5.p(x)=5x^2+5x+4

D=(5)^2-4(5)(4)=25-80

D=-55

Hence, the function have no two real number zeroes.

6.r(x)=x^2-2x-15

D=(-2)^2-4(1)(-15)=4+60=64

D>0

Hence, function have two real zeroes.

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Step-by-step explanation:

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3 years ago
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Eduardwww [97]

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Step-by-step explanation:

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3 0
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Each cube in this solid figure is a unit cube.<br><br> What is the volume of this solid figure?
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Answer:

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Step-by-step explanation:

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