Answer:
3:4.
Step-by-step explanation:
To work this out we need to find the highest multiple of 45 and 60.
15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.
45 divided by 15 = 3
60 divided by 15 = 4
Therefore the odds of selecting a red candy is 3:4.
Hope that helps. x
<span>5 1/4 + x + 6 5/6 + 4 2/3 = 22 1/6
5 3/12 + x + 6 10/12 + 4 8/12 = 22 2/12
15 21/12 + x = 22 2/13
</span>16 9/12<span> + x = 22 2/12
x = 22 2/12 - </span>16 9/12<span>
x = </span>21 14/12 - 16 9/12
x = 5 5/12
answer is <span>A. 5 5/12</span>
Answer:
6 squares to right and 6 squares down
Step-by-step explanation:
Go with the coordinate (-1, 5) on shape A
Hope it helps :)
Until the concerns I raised in the comments are resolved, you can still set up the differential equation that gives the amount of salt within the tank over time. Call it

.
Then the ODE representing the change in the amount of salt over time is



and this with the initial condition

You have


![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/250}A(t)\right]=\dfrac25e^{t/250}(1+\cos t)](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F250%7DA%28t%29%5Cright%5D%3D%5Cdfrac25e%5E%7Bt%2F250%7D%281%2B%5Ccos%20t%29)
Integrating both sides gives


Since

, you get

so the amount of salt at any given time in the tank is

The tank will never overflow, since the same amount of solution flows into the tank as it does out of the tank, so with the given conditions it's not possible to answer the question.
However, you can make some observations about end behavior. As

, the exponential term vanishes and the amount of salt in the tank will oscillate between a maximum of about 100.4 lbs and a minimum of 99.6 lbs.
A. 125 is the answer to your question