Cyclins drive the events of the cell cycle by partnering with a family of enzymes called the cyclin-dependent kinases (Cdks). A lone Cdk is inactive, but the binding of a cyclin activates it, making it a functional enzyme and allowing it to modify target proteins.
hope this helps!
Hello there!
5d = 17.1
The equation is asking you to find the value for "d". How to do that? Well, all you have to do is divide both side by 5.
5d/5 = 17.1
d = 3.42
That's your answer!
You can even double check your work, if you want to. How? Well, you just need to replace 3.42 where it belongs.
5(3.42) = 17.1
17.1 = 17.1
True!
Let me know if you have additional questions. As always, it is my pleasure to help students like you!
Answer:
EG = 2 units
Step-by-step explanation:
Given that line q bisects EG at T , then
ET = TG ( substitute values )
x = x - 2 ( multiply through by 3 to clear the fraction )
x = 3x - 6 ( subtract x from both sides )
0 = 2x - 6 ( add 6 to both sides )
6 = 2x ( divide both sides by 2 )
3 = x
Then
ET = x = × 3 = 1
TG = x - 2 = 3 - 2 = 1
Thus
EG = ET + TG = 1 + 1 = 2 units
Answer:
32
Step-by-step explanation:
add
Answer:
Step-by-step explanation:
a)3*4*2*b = 24b
Multiply the numerals and then the variables.When multiply variables, add the exponents and only same variables can be multiplied
b) c⁵ *c = c⁵⁺¹ = c⁶
c) 2y⁴ *5y³ = 2*5 * y⁴⁺³ = 10y⁷
