Answer: 
Step-by-step explanation:
To answer this, we have to use quadratic equations.
We can represent this by using information given to us.
Knowing that a parabola peaks at its vertex, and the flare goes from its launch site (x = 0) and hits the ground 30m from the launch site (x = 30), we know that the flare peaks 15 meters away horizontally from the launch point.
We also know that the y-intercept is 0, because it is fired from the ground.
Knowing that the vertex for the parabola is (15, 200) and the y-intercept is (0, 0), we can model an equation.
Vertex form is:
, where (h, k) is the vertex.

We can plug the y-intercept, (0, 0), into this equation to find a:

Cos θ = adjacent / hypothenus = 5/13
opposite = sqrt(hypothenus^2 - adjacent^2) = sqrt(13^2 - 5^2) = sqrt(169 - 25) = sqrt(144) = 12
sec θ = 1/cos θ = 1/(adjacent / hypothenus) = hypothenus / adjacent = 13/5
cot θ = 1/tan θ = 1/(opposite/adjacent) = adjacent / opposite = 5/12
sec θ = 13/5
cot θ = 5/12
Step-by-step explanation:
I'm sorry that i cannot answer your question but i need these points badly for my questions for some missing assignments i have sorry
Answer:
The expected cost is 152
Step-by-step explanation:
Recall that since Y is uniformly distributed over the interval [1,5] we have the following probability density function for Y
if
and 0 othewise. (To check this is the pdf, check the definition of an uniform random variable)
Recall that, by definition

Also, we are given that
. Recall the following properties of the expected value. If X,Y are random variables, then

Then, using this property we have that
.
Thus, we must calculate E[Y] and E[Y^2].
Using the definition, we get that
![E[Y] = \int_{1}^{5}\frac{y}{4} dy =\frac{1}{4}\left\frac{y^2}{2}\right|_{1}^{5} = \frac{25}{8}-\frac{1}{8} = 3](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%20%5Cint_%7B1%7D%5E%7B5%7D%5Cfrac%7By%7D%7B4%7D%20dy%20%3D%5Cfrac%7B1%7D%7B4%7D%5Cleft%5Cfrac%7By%5E2%7D%7B2%7D%5Cright%7C_%7B1%7D%5E%7B5%7D%20%3D%20%5Cfrac%7B25%7D%7B8%7D-%5Cfrac%7B1%7D%7B8%7D%20%3D%203)
![E[Y^2] = \int_{1}^{5}\frac{y^2}{4} dy =\frac{1}{4}\left\frac{y^3}{3}\right|_{1}^{5} = \frac{125}{12}-\frac{1}{12} = \frac{31}{3}](https://tex.z-dn.net/?f=E%5BY%5E2%5D%20%3D%20%5Cint_%7B1%7D%5E%7B5%7D%5Cfrac%7By%5E2%7D%7B4%7D%20dy%20%3D%5Cfrac%7B1%7D%7B4%7D%5Cleft%5Cfrac%7By%5E3%7D%7B3%7D%5Cright%7C_%7B1%7D%5E%7B5%7D%20%3D%20%5Cfrac%7B125%7D%7B12%7D-%5Cfrac%7B1%7D%7B12%7D%20%3D%20%5Cfrac%7B31%7D%7B3%7D)
Then

Answer:
Because here score is 575 she must pay 2365 per mo according to the table
If her score were 850 she would pay 1685 per month
So the difference in the two rates is:
2365 - 1685 = 680 a month more because of the low credit score