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horrorfan [7]
3 years ago
10

A food truck sells salads for $6.50 each and drinks for $2.00 each. The food truck’s revenue from selling a total of 209 salads

and drinks in one day was $836.50. How many salads were sold that day? A) 77 B) 93 C) 99 D) 105
Mathematics
2 answers:
lord [1]3 years ago
6 0
Create an equation to figure out how much salad was sold that day. S is for the number of salads. D is for the number of drinks.

$6.5s + $2d = $836.5
<span>s + d = 209
</span><span>s = 209 - d

Plug in the values. 

</span>6.5 (209 - d) + 2d = 836.5

1358.5 - 6.5d + 2d = 836.5
-4.5d = -522
d = 116

<span>s = 209 - 116
= 93
</span>
Answer: Letter B ✅

Hope that helps! ★ If you have further questions about this question or need more help, feel free to comment below or post another question and send the link to me. -UnicornFudge aka Nadia 
lana [24]3 years ago
5 0
Its d I think I'm not sure I'm in class so I can't help that well
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2 years ago
Trevor and marissa together have 26 t-shirts to sell. If marissa has 6 fewer tshirts that trevor, find hiw many tshirts trevor h
Eva8 [605]

Answer:

Number of t-shirts Trevor have are 16

If Trevor have 16 t-shirts, than Marissa will have 10 t-shirts.

Step-by-step explanation:

Let, the number of t-shirts Trevor has = x and number of t-shirts Marissa has = y.

Since, they both have total of 26 t-shirts. We get,

x+y=26

Moreover, Marissa has 6 t-shirts less than that of Trevor.

So, we have,

y=x-6

On solving the system of equations, we get,

x+y=26 implies x+x-6=26 implies 2x=26+6 i.e. 2x= 32 i.e. x= 16.

So, y=x-6 implies y=16-6 i.e y= 10.

Hence, the number of t-shirts Trevor and Marissa have are 16 and 10 respectively.

That is, If Trevor have 16 t-shirts, than Marissa will have 10 t-shirts.

8 0
3 years ago
Consider the following function.
Kryger [21]

Answer:

See below

Step-by-step explanation:

I assume the function is f(x)=1+\frac{5}{x}-\frac{4}{x^2}

A) The vertical asymptotes are located where the denominator is equal to 0. Therefore, x=0 is the only vertical asymptote.

B) Set the first derivative equal to 0 and solve:

f(x)=1+\frac{5}{x}-\frac{4}{x^2}

f'(x)=-\frac{5}{x^2}+\frac{8}{x^3}

0=-\frac{5}{x^2}+\frac{8}{x^3}

0=-5x+8

5x=8

x=\frac{8}{5}

Now we test where the function is increasing and decreasing on each side. I will use 2 and 1 to test this:

f'(2)=-\frac{5}{2^2}+\frac{8}{2^3}=-\frac{5}{4}+\frac{8}{8}=-\frac{5}{4}+1=-\frac{1}{4}

f'(1)=-\frac{5}{1^2}+\frac{8}{1^3}=-\frac{5}{1}+\frac{8}{1}=-5+8=3

Therefore, the function increases on the interval (0,\frac{8}{5}) and decreases on the interval (-\infty,0),(\frac{8}{5},\infty).

C) Since we determined that the slope is 0 when x=\frac{8}{5} from the first derivative, plugging it into the original function tells us where the extrema are. Therefore, f(\frac{8}{5})=1+\frac{5}{\frac{8}{5}}-\frac{4}{\frac{8}{5}^2 }=\frac{41}{16}, meaning there's an extreme at the point (\frac{8}{5},\frac{41}{16}), but is it a maximum or minimum? To answer that, we will plug in x=\frac{8}{5} into the second derivative which is f''(x)=\frac{10}{x^3}-\frac{24}{x^4}. If f''(x)>0, then it's a minimum. If f''(x), then it's a maximum. If f''(x)=0, the test fails. So, f''(\frac{8}{5})=\frac{10}{\frac{8}{5}^3}-\frac{24}{\frac{8}{5}^4}=-\frac{625}{512}, which means (\frac{8}{5},\frac{41}{16}) is a local maximum.

D) Now set the second derivative equal to 0 and solve:

f''(x)=\frac{10}{x^3}-\frac{24}{x^4}

0=\frac{10}{x^3}-\frac{24}{x^4}

0=10x-24

-10x=-24

x=\frac{24}{10}

x=\frac{12}{5}

We then test where f''(x) is negative or positive by plugging in test values. I will use -1 and 3 to test this:

f''(-1)=\frac{10}{(-1)^3}-\frac{24}{(-1)^4}=-34, so the function is concave down on the interval (-\infty,0)\cup(0,\frac{12}{5})

f''(3)=\frac{10}{3^3}-\frac{24}{3^4}=\frac{2}{27}>0, so the function is concave up on the interval (\frac{12}{5},\infty)

The inflection point is where concavity changes, which can be determined by plugging in x=\frac{12}{5} into the original function, which would be f(\frac{12}{5})=1+\frac{5}{\frac{12}{5}}+\frac{4}{\frac{12}{5}^2 }=\frac{43}{18}, or (\frac{12}{5},\frac{43}{18}).

E) See attached graph

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borishaifa [10]
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