(2x+5y=60)
- (2x-5y=-20)
-------------------
10y=80
y=8
2x+5(8)=60
2x+40=60
2x=20
x=10
(A)






(B)




But we assume
is a function of
alone, so there is not potential function here.
(C)






For (A) and (C), we have
, which makes
for both.
Hello,
f(x)-f(a)= -3x²-5x+1-(-3a²-5a+1)=-3(x²-a²)-5(x-a)=-3(x-a)(x+a)-5(x-a)
=-(x-a)(3(x+a)+5)
=-(x-a)(3x+3a+5)
lim (f(x)-f(a))/(x-a)=- lim (3x+3a+5)=3a+3a+5=-6a-5
if a=1==>-6*1-5=-11
Otherwise
f'(x)=-6x-5
f'(1)=-6-5=-11
at point(1,-7)
The probability of you rolling a 5 would be 1/6 since the cube has 6 sides and only one of the sides has a 5.
The probability that you either roll a 5 or do not roll a 5 would be 6/6 because 1/6, the probability you WILL roll a 5, and 5/6, the probability you WON'T roll a 5 added together is 6/6.
The probability that you don't roll a 5 is 5/6 because there are 5 sides of the dice that are not 5.
Hope that helped!
Answer:
The largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb
Step-by-step explanation:
Given
μ = Mean = 10.4 lb
σ = Standard deviation = 3 lb
Using a confidence level of 90%,
We'll need to first determine the z value that correspond with bottom 5% of consumption of banana
α = 5%
α = 0.05
So,
zα = z(0.05)
z(0.05) = -1.645 ----- From z table
Let x represent the largest annual per capita consumption of bananas
The relationship between x and z is
x = μ + zσ
By substitution;
x = 10.4 + (-1.645) * 3
x = 10.4 - 4.935
x = 5.465
Hence, the largest annual per capita consumption of bananas in the bottom 5% of consumption is 5.465 lb