Differentiate using the chain rule:
d/du [ln(u)] d/dx[2x^3+3x]
derivative of ln(u) = 1/u
1/u d/dx[2x^3+3x]
1/2x^3+3x d/dx[2x^3+3x]
Differentiate
(6x^2+3) 1/2x^3+3x
Simplify
Dy/dx = 3(2x^2+1) / x(2x^2 +3)
Answer:(
gof) = 12x+8
Step-by-step explanation:
to find gof plug f into g :
(g o f) = 6(2x+1)+2
then simplify:
( g o f) = 12x+8
Graph is your answer look below for proof
have a good day!
The volume of a box like this is found by multiplying the length times the width times the height. We are told that the length is 8 more inches than the width, so the width is w and the length is w + 8. If we cut away 3 square inches from each corner, the height when we fold up those corners is going to be 3. The volume is given as 27, so our formula looks like this:

. When we do that multiplication, we have

. We need to solve for w so we can then solve for h. Move the 27 over and set the quadratic equal to 0.

. We can then factor out a 3 to make the job easier:

. Now we can factor to solve for w. The 2 numbers that add up to 8 and multiply to -9 are 9 and -1. So (w+9) = 0, (w-1) = 0, or 3 = 0. Of course 3 doesn't equal 0, so that's out. w + 9 = 0 so w = -9. w - 1 = 0 so w = 1. There are 2 things in math that can never EVER be negative and those are time and distance/length. So -9 is out. That means that w = 1. But don't forget that there was 6 inches cut off each side, so the width is 1 + 3 + 3 which is 7. The length is w + 8 which means that the length is 7 + 8 or 15. Those are the dimensions of the rectangle before it was cut.
We first recall the formula for the volume of a rectangular box:

where l is its length, w is the width, and h is the height.
According to the problem, the height is 3 inches less than the width therefore we can replace h with the term

. Additionally, the length of the box is 2 inches more than twice the width therefore the length can also be replaced with

.
We can notice that the equation will just have one unknown variable because we already know the volume of the box. We can then solve for this variable (w):




Solving the cubic equation we'll get

and two complex number solutions. We'll just need to solve for the length and height using the value of the width:

ANSWER: The width of the box is 10 inches; its length is 22 inches, and its height is 7 inches.